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Question 91 of 104

Q.If A={1,2,3,4}A = \{1, 2, 3, 4\}; B={3,4,5,6}B = \{3, 4, 5, 6\} find n((A∪B)×(A∩B)×(AΔB))n((A\cup B) \times (A\cap B) \times (A\Delta B)).

Tamil Nadu DgeTamil Nadu HSC First Year (DGE) Board 2023Subjective· 2mImportance★★★★★
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Concept understanding — Cartesian Product

Cartesian Product: From Intuition to Definition

Imagine you're ordering a pizza. You have two choices to make: the size (Small, Medium, Large) and the topping (Cheese, Pepperoni, Veggie). How many different pizzas can you order?

You can pair each size with each topping:

  • Small + Cheese, Small + Pepperoni, Small + Veggie
  • Medium + Cheese, Medium + Pepperoni, Medium + Veggie
  • Large + Cheese, Large + Pepperoni, Large + Veggie

That's 3×3=93 \times 3 = 9 possible pizzas. What you just did — systematically pairing every element of one set with every element of another — is the Cartesian product in action.


The Intuition

The Cartesian product is a way to combine two sets to create a new set of ordered pairs. The order matters: (Small, Cheese) is different from (Cheese, Small) — one is a pizza order, the other is nonsense.

Think of it like a multiplication table for sets. If set AA has mm items and set BB has nn items, their Cartesian product has m×nm \times n items.

Note

The name comes from René Descartes, who used this idea to create the coordinate plane — every point (x,y)(x, y) on a graph is an element of the Cartesian product of the x-axis and y-axis.


The Precise Definition

Let AA and BB be two sets. The Cartesian product of AA and BB, written A×BA \times B, is the set of all ordered pairs (a,b)(a, b) where aa is from AA and bb is from BB.

A×B={(a,b)∣a∈A and b∈B}A \times B = \{(a, b) \mid a \in A \text{ and } b \in B\}

The vertical bar means "such that." So read it as: "The set of all ordered pairs (a, b) such that a belongs to A and b belongs to B."


Key Properties to Remember

  1. Order matters: A×BA \times B is generally not the same as B×AB \times A. For example, if A={1,2}A = \{1, 2\} and B={x,y}B = \{x, y\}:

    • A×B={(1,x),(1,y),(2,x),(2,y)}A \times B = \{(1, x), (1, y), (2, x), (2, y)\}
    • B×A={(x,1),(x,2),(y,1),(y,2)}B \times A = \{(x, 1), (x, 2), (y, 1), (y, 2)\}

    These are different sets because the pairs are ordered differently.

  2. Size formula: If ∣A∣=m|A| = m and ∣B∣=n|B| = n, then ∣A×B∣=m×n|A \times B| = m \times n. This holds even if one set is empty — then the product is empty.

  3. Empty set: A×∅=∅A \times \emptyset = \emptyset and ∅×B=∅\emptyset \times B = \emptyset. You can't form any pairs if one set has nothing to contribute.

Watch out

A common mistake: thinking A×BA \times B contains all possible combinations of elements from AA and BB without caring about order. But (a,b)(a, b) and (b,a)(b, a) are different pairs unless a=ba = b. Always treat ordered pairs as distinct based on position.


Examples to Cement the Idea

Example 1: A={1,2}A = \{1, 2\}, B={3,4}B = \{3, 4\}

A×B={(1,3),(1,4),(2,3),(2,4)}A \times B = \{(1, 3), (1, 4), (2, 3), (2, 4)\}

Four pairs, as expected (2×2=42 \times 2 = 4).

Example 2: A={a}A = \{a\}, B={1,2,3}B = \{1, 2, 3\}

A×B={(a,1),(a,2),(a,3)}A \times B = \{(a, 1), (a, 2), (a, 3)\}

Three pairs — every element of BB gets paired with the single element of AA.

Example 3: A={0,1}A = \{0, 1\}, B={0,1}B = \{0, 1\}

A×B={(0,0),(0,1),(1,0),(1,1)}A \times B = \{(0, 0), (0, 1), (1, 0), (1, 1)\}

This is the set of all possible 2-bit binary strings — a foundation for computer science.


Why This Matters

The Cartesian product is the mathematical backbone of: …

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