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Exercise 6.1 · Q4

Q.Find the value of kk and bb, if the points P(−3,1)P(-3, 1) and Q(2,b)Q(2, b) lie on the locus of x2−5x+ky=0x^2 - 5x + ky = 0.

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Both points satisfy the locus equation x2−5x+ky=0x^2-5x+ky=0, so substitute each in turn.

Step 1. Substitute P(−3,1)P(-3,1). Since PP lies on the locus,

(−3)2−5(−3)+k(1)=0  ⇒  9+15+k=0  ⇒  24+k=0  ⇒  k=−24.(-3)^2-5(-3)+k(1)=0 \;\Rightarrow\; 9+15+k=0 \;\Rightarrow\; 24+k=0 \;\Rightarrow\; k=-24.

Step 2. Substitute Q(2,b)Q(2,b) using k=−24k=-24. Since QQ also lies on the locus, …

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