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Exercise 6.5 · Q20

Q.If a vertex of a square is at the origin and one of its sides lies along the line 4x+3y−20=04x+3y-20=0, then the area of the square is

(1) 2020 sq. units
(2) 1616 sq. units
(3) 2525 sq. units
(4) 44 sq. units
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The side length through the origin-vertex equals the perpendicular distance from the origin to 4x+3y−20=04x+3y-20=0, which is 44; area =42=16=4^2=16.

A square has a vertex at the origin, and one of its sides (not through this vertex) lies along 4x+3y−20=04x+3y-20=0. The two sides of the square meeting at the origin are perpendicular to this given side, so the side-length of the square equals the perpendicular distance from the origin to the line 4x+3y−20=04x+3y-20=0.

Step 1. Apply the perpendicular-distance formula from (0,0)(0,0) to 4x+3y−20=04x+3y-20=0 (here a=4,b=3,c=−20a=4,b=3,c=-20):

d=∣4(0)+3(0)−20∣42+32=2025=205=4d=\dfrac{|4(0)+3(0)-20|}{\sqrt{4^2+3^2}}=\dfrac{20}{\sqrt{25}}=\dfrac{20}{5}=4 …

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