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Physics · Ch 5 — Motion of System of Particles and Rigid Bodies

Principle of Moments

5.3.3

Principle of Moments

Consider a light rod (of negligible mass) pivoted at a single point along its length, with two parallel forces F1F_1 and F2F_2 acting at its two ends, at distances d1d_1 and d2d_2 respectively from the pivot, along with the pivot's own normal reaction force NN. For the rod to remain stationary and horizontal, it must be in both translational and rotational equilibrium — both the net force and the net torque on it must be zero.

Net force zero:

−F1+N−F2=0⇒N=F1+F2-F_1+N-F_2=0\quad\Rightarrow\quad N=F_1+F_2

(the pivot's upward reaction exactly balances the two downward forces).

Net torque zero, taken about the pivot itself (so that NN, passing through the pivot, contributes no torque there):

d1F1−d2F2=0⇒d1F1=d2F2.d_1F_1-d_2F_2=0\quad\Rightarrow\quad d_1F_1=d_2F_2.

This is the principle of moments: for the rod to balance about its pivot, the turning moment on one side must exactly equal the turning moment on the other side. It can also be rearranged as F1F2=d2d1\dfrac{F_1}{F_2}=\dfrac{d_2}{d_1}.

This principle is exactly what makes a beam balance used for weighing goods work, in the special symmetric case d1=d2d_1=d_2 and F1=F2F_1=F_2. …

Figure 5.15Principle of moments on a pivoted rod

What this figure shows. A light rod is pivoted at a point where a normal reaction force N acts upward; on either side of the pivot, forces F1 and F2 act downward at distances d1 and d2 respectively from the pivot, illustrating the balance condition d1 F1 = d2 F2 that keeps the rod in both translational and rotational equilibr …