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Physics · Ch 10 — Oscillations

Time period, frequency, phase, phase difference and epoch in SHM

10.2.3

Time period, frequency, phase, phase difference and epoch in SHM

The time period TT is the time taken to complete one full oscillation. Since one complete revolution on the reference circle corresponds to ωt=2π\omega t=2\pi, setting t=Tt=T gives ωT=2π\omega T=2\pi, so T=2π/ωT=2\pi/\omega. The displacement can then be written as y(t)=Asin⁡ ⁣(2πTt)y(t)=A\sin\!\left(\dfrac{2\pi}{T}t\right); replacing tt by t+Tt+T leaves the sine unchanged since sin⁡(θ+2π)=sin⁡θ\sin(\theta+2\pi)=\sin\theta, confirming y(t+T)=y(t)y(t+T)=y(t) -- the formal definition of a periodic function. Frequency ff is the number of complete oscillations per second, related to the period by f=1/Tf=1/T, SI unit s−1^{-1} or hertz (Hz). Angular frequency ω\omega (cycles per second expressed in radians) is related to ff by ω=2πf\omega=2\pi f, SI unit rad s−1^{-1}. The phase of a vibrating particle at any instant, φ=ωt+φ0\varphi=\omega t+\varphi_0, completely specifies its position and direction of motion relative to the mean position; the general displacement equation is y=Asin⁡(ωt+φ0)y=A\sin(\omega t+\varphi_0). At t=0t=0, the phase equals φ0\varphi_0, called the epoch (initial phase), and φ0\varphi_0 itself is the angle of epoch. For two SHMs of the same ω\omega but different epochs, y1=Asin⁡(ωt+φ1)y_1=A\sin(\omega t+\varphi_1) and y2=Asin⁡(ωt+φ2)y_2=A\sin(\omega t+\varphi_2), the phase difference is the constant Δφ=φ2−φ1\Delta\varphi=\varphi_2-\varphi_1. Differentiating the displacement eq …

Figure 10.11The phase of a vibrating particle at two instants of time

What this figure shows. A sinusoidal displacement-versus-time curve is drawn with two marked instants, t = 0 (where the curve sits at height A sin(phi_i), the epoch) and a later instant t_i (where the curve sits at height A sin(phi(t_i))). Arrows indicate the phase angle at each instant, phi_i at t = 0 and phi(t_i) = omega t_i + phi_i later, together with the amplitude envelope +A to -A and the period 2 pi/omega marked along the time axis, illustrating that the phase is simply the running angle argument of the sine function that pins down exactly where in its cy …

Misc Example 10.5Heart beat frequency from time period

Worked out. A nurse reports a patient's average heartbeat time period as 0.8 s, and the question asks for this rate expressed as beats per minute. Frequency is the reciprocal of the time period, so f = 1/T = 1/0.8 = 1.25 per second. Since one minute contains 60 seconds, converting from beats-per-second to beats-per-minute means multiplying by 60: f = 1.25 x 60 = 75 beats per minute, a normal resting heart rate, showing the everyday usefulness of the simple T-to-f conversion for a genui …

Misc Example 10.6Amplitude, angular frequency and phase from a given SHM equation

Worked out. Three different SHM equations are given -- y = 0.3 sin(40 pi t + 1.1), y = 2 cos(pi t), and y = 3 sin(2 pi t - 1.5) -- and the task is to read off amplitude, angular frequency, frequency, time period, and initial phase directly from each, by matching each equation to the standard form y = A sin(omega t + phi0). For the first, A = 0.3 units, omega = 40 pi rad/s, so f = omega/(2 pi) = 20 Hz and T = 1/f = 0.05 s, with initial phase phi0 = 1.1 rad. For the second, A = 2 units, omega = pi rad/s, f = 0.5 Hz, T = 2 s, and phi0 = 0 rad (a pure cosine has zero phase relative to the cosine reference). For the third, A = 3 units, omega = 2 pi rad/s, f = 1 Hz, T = 1 s, and phi0 = 1.5 rad, reading each constant straight off …

Misc Example 10.7Phase differences between displacement, velocity and acceleration

Worked out. Starting from displacement y = A sin(omega t), the task is to show that the phase difference between displacement and velocity is pi/2 (90 degrees), between velocity and acceleration is also pi/2, and between displacement and acceleration is pi (180 degrees). Differentiating once gives velocity v = A omega cos(omega t), which can be rewritten as A omega sin(omega t + pi/2) using the cosine-to-sine identity, so velocity leads displacement by exactly pi/2. Differentiating again gives acceleration a = -A omega^2 sin(omega t), rewritten as A omega^2 sin(omega t + pi) using sin(theta+pi) = -sin(theta), so acceleration leads velocity by a further pi/2, and therefore leads displacement itself by pi/2 + pi/2 = pi, i.e. is exactly out of step with displacement (always pointing the opposite way when the sign co …