Physics · Ch 10 — Oscillations
Time period, frequency, phase, phase difference and epoch in SHM
Time period, frequency, phase, phase difference and epoch in SHM
The time period is the time taken to complete one full oscillation. Since one complete revolution on the reference circle corresponds to , setting gives , so . The displacement can then be written as ; replacing by leaves the sine unchanged since , confirming -- the formal definition of a periodic function. Frequency is the number of complete oscillations per second, related to the period by , SI unit s or hertz (Hz). Angular frequency (cycles per second expressed in radians) is related to by , SI unit rad s. The phase of a vibrating particle at any instant, , completely specifies its position and direction of motion relative to the mean position; the general displacement equation is . At , the phase equals , called the epoch (initial phase), and itself is the angle of epoch. For two SHMs of the same but different epochs, and , the phase difference is the constant . Differentiating the displacement eq …
What this figure shows. A sinusoidal displacement-versus-time curve is drawn with two marked instants, t = 0 (where the curve sits at height A sin(phi_i), the epoch) and a later instant t_i (where the curve sits at height A sin(phi(t_i))). Arrows indicate the phase angle at each instant, phi_i at t = 0 and phi(t_i) = omega t_i + phi_i later, together with the amplitude envelope +A to -A and the period 2 pi/omega marked along the time axis, illustrating that the phase is simply the running angle argument of the sine function that pins down exactly where in its cy …
Worked out. A nurse reports a patient's average heartbeat time period as 0.8 s, and the question asks for this rate expressed as beats per minute. Frequency is the reciprocal of the time period, so f = 1/T = 1/0.8 = 1.25 per second. Since one minute contains 60 seconds, converting from beats-per-second to beats-per-minute means multiplying by 60: f = 1.25 x 60 = 75 beats per minute, a normal resting heart rate, showing the everyday usefulness of the simple T-to-f conversion for a genui …
Worked out. Three different SHM equations are given -- y = 0.3 sin(40 pi t + 1.1), y = 2 cos(pi t), and y = 3 sin(2 pi t - 1.5) -- and the task is to read off amplitude, angular frequency, frequency, time period, and initial phase directly from each, by matching each equation to the standard form y = A sin(omega t + phi0). For the first, A = 0.3 units, omega = 40 pi rad/s, so f = omega/(2 pi) = 20 Hz and T = 1/f = 0.05 s, with initial phase phi0 = 1.1 rad. For the second, A = 2 units, omega = pi rad/s, f = 0.5 Hz, T = 2 s, and phi0 = 0 rad (a pure cosine has zero phase relative to the cosine reference). For the third, A = 3 units, omega = 2 pi rad/s, f = 1 Hz, T = 1 s, and phi0 = 1.5 rad, reading each constant straight off …
Worked out. Starting from displacement y = A sin(omega t), the task is to show that the phase difference between displacement and velocity is pi/2 (90 degrees), between velocity and acceleration is also pi/2, and between displacement and acceleration is pi (180 degrees). Differentiating once gives velocity v = A omega cos(omega t), which can be rewritten as A omega sin(omega t + pi/2) using the cosine-to-sine identity, so velocity leads displacement by exactly pi/2. Differentiating again gives acceleration a = -A omega^2 sin(omega t), rewritten as A omega^2 sin(omega t + pi) using sin(theta+pi) = -sin(theta), so acceleration leads velocity by a further pi/2, and therefore leads displacement itself by pi/2 + pi/2 = pi, i.e. is exactly out of step with displacement (always pointing the opposite way when the sign co …