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Physics · Ch 11 — Waves

Factors Affecting Speed of Sound in Gases

11.4.3

Factors Affecting Speed of Sound in Gases

Rewriting the Laplace speed-of-sound formula using the ideal gas equation of state, PV=μRTPV=\mu RT (with μ\mu the number of moles, RR the universal gas constant), and substituting ρ=M/V\rho=M/V (with MM the molar mass) gives the fully explicit form v=γRT/Mv=\sqrt{\gamma RT/M}, which makes each of the following practical dependencies transparent. Effect of pressure: at a fixed temperature, if pressure varies then density varies in exact proportion, so the ratio P/ρP/\rho -- and hence the speed of sound -- stays constant; sound speed is therefore independent of pressure alone (though the speed does genuinely differ at different altitudes, because temperature, not pressure directly, differs there). Effect of temperature: since v∝Tv\propto\sqrt{T}, sound speed increases with the square root of the absolute temperature; using a binomial expansion around 0 degC (273 K), this can be approximated by the linear relation v=(331+0.61t) m/sv=(331+0.61t)\ \text{m/s} for temperature tt in degrees Celsius, i.e. sound speed rises by about 0.61 m/s for every 1 degree Celsius increase, because warmer molecules carry more thermal energy and vibrate faster. Effect of density: comparing two gases at the same temperature and pressure but different densities ρ1,ρ2\rho_1,\rho_2 (and the same γ\gamma) gives v1/v2=ρ2/ρ1v_1/v_2=\sqrt{\rho_2/\rho_1} -- sound travels more slowly through a denser gas. Effect of moisture (humidity): moist air is about 0.625 times as dense as dry air at the same pressure, so increasing humidity lowers air densit …

Misc Example 11.9Equal-speed temperature for sound in oxygen versus nitrogen

Worked out. The densities of oxygen and nitrogen are in the ratio 16:14, and the speed of sound in nitrogen at 17 ∘C17\,^{\circ}\text{C} (290 K) is given as equal to the speed of sound in oxygen at some unknown temperature t; the task is to find that temperature t. Writing the speed of sound in each gas using v=γRT/Mv=\sqrt{\gamma RT/M} and setting the two speeds equal (with a common γ\gamma) gives, after squaring and cancelling common factors, the relation MN/290=MO/(273+t)M_N/290 = M_O/(273+t). Since the density ratio at the same conditions equals the molar mass ratio, ρO/ρN=MO/MN=16/14\rho_O/\rho_N = M_O/M_N = 16/14, substituting this ratio into the temperature relation and solving the resulting linear equation for t gives 273+t=290×(16/14)273+t = 290\times(16/14), which works out to t≈58.4 ∘Ct\approx58.4\,^{\circ}\text{C}. The example shows how the temperature-dependence and density-dependence of sound speed in gases (both following from the same underlying formula v=γRT/Mv=\sqrt{\gamma RT/M}) can be combined to solve …