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Physics · Ch 11 — Waves

Particle Velocity and Wave Velocity

11.6.4

Particle Velocity and Wave Velocity

Two distinct velocities arise in describing a progressive wave, and confusing them is one of the most common conceptual errors students make. The particle velocity, vP=∂y/∂tv_P=\partial y/\partial t, is the instantaneous rate of change of displacement of one single, specific particle of the medium at its own fixed location; for the standard sinusoidal wave y(x,t)=Asin⁡(kx−ωt)y(x,t)=A\sin(kx-\omega t), differentiating with respect to time at fixed xx gives vP=−ωAcos⁡(kx−ωt)v_P=-\omega A\cos(kx-\omega t), which oscillates sinusoidally between −ωA-\omega A and +ωA+\omega A and differs from particle to particle across the wave at any given instant. The wave (or phase) velocity, v=ω/kv=\omega/k, by contrast, is the constant speed at which a single point of fixed phase -- such as a particular crest -- itself moves through the medium; it is derived by requiring that the total phase kx−ωtkx-\omega t stay exactly constant as both xx and tt change together while tracking that one point, which on rearranging gives dx/dt=ω/k=vdx/dt=\omega/k=v. Physically these describe completely different motions: the wave velocity carries the overall pattern steadily forward through space at a fixed rate, exactly as computed from v=fλv=f\lambda, while any one individual particle of the medium never actually travels anywhere at all -- it only ever oscillates back and forth about its own fixed …

Misc Example 11.15Wavelength of a mobile phone tower's transmitted signal

Worked out. A mobile phone tower transmits a wave signal of frequency 900 MHz, and the task is to compute the wavelength of the waves it transmits, treating the signal as an electromagnetic wave travelling at the speed of light, c=3×108 m/sc=3\times10^8\ \text{m/s}. Converting the frequency to SI units, f=900 MHz=900×106 Hzf=900\ \text{MHz}=900\times10^6\ \text{Hz}, and applying the fundamental wave relation rearranged as λ=v/f\lambda=v/f (here using c in place of v, since this is an electromagnetic rather than a mechanical wave) gives λ=(3×108)/(900×106)=0.33 m\lambda=(3\times10^8)/(900\times10^6)=0.33\ \text{m}. The example demonstrates that the same wave relation v=fλv=f\lambda used throughout the chapter for mechanical sound and string waves applies equally to electromagnetic waves, simply substituting the speed of light for the mechanical wave speed, and shows that the very high frequencies used in mobile communication correspond to wavelengths on the order of tens o …