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Question 15 of 44

Q.The total cost of 1111 pencils and 33 erasers is ₹ 64\text{₹ } 64 and the total cost of 88 pencils and 33 erasers is ₹ 49\text{₹ } 49. Find the cost of each pencil and each eraser by Cramer's rule.

Tamil Nadu DgeTamil Nadu HSC (DGE) Commerce Board 2020Subjective· 2mImportance★★★★★
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Set up 11x+3y=6411x + 3y = 64, 8x+3y=498x + 3y = 49 with x=x = pencil cost, y=y = eraser cost. Cramer's rule gives Δ=9\Delta = 9, Δx=45\Delta_x = 45, Δy=27\Delta_y = 27, so x=5x = 5 and y=3y = 3.

Step 1 — Frame the equations. Let the cost of one pencil be xx and one eraser be yy (in ₹):

11x+3y=64,8x+3y=49.11x + 3y = 64, \qquad 8x + 3y = 49.

Step 2 — Coefficient determinant.

Δ=∣11383∣=(11)(3)−(3)(8)=33−24=9 (≠0).\Delta = \begin{vmatrix} 11 & 3 \\ 8 & 3 \end{vmatrix} = (11)(3) - (3)(8) = 33 - 24 = 9 \ (\neq 0).

Step 3 — Determinants for xx and yy (replace the respective column by the constants 64,4964, 49):

Δx=∣643493∣=(64)(3)−(3)(49)=192−147=45,\Delta_x = \begin{vmatrix} 64 & 3 \\ 49 & 3 \end{vmatrix} = (64)(3) - (3)(49) = 192 - 147 = 45, …

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