Skip to content
Worked Examples · Example 4

Q.Test the consistency of the system x+y+z=6x+y+z=6, 2x+2y+2z=122x+2y+2z=12, x−y+2z=5x-y+2z=5 using the rank method.

Tamil Nadu DgeTextbookSubjectiveImportance★★★★★
16% · 7/44 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Row-reducing the augmented matrix [A∣B]=(111∣6222∣121−12∣5)[A|B]=\begin{pmatrix}1&1&1&|&6\\2&2&2&|&12\\1&-1&2&|&5\end{pmatrix}

R2→R2−2R1R_2\to R_2-2R_1: [2−2,2−2,2−2 ∣ 12−12]=[0,0,0 ∣ 0][2-2,2-2,2-2\,|\,12-12]=[0,0,0\,|\,0] — an entirely zero row (both sides), confirming equation 2 is redundant, not contradictory.

(111∣6000∣01−12∣5)\begin{pmatrix}1&1&1&|&6\\0&0&0&|&0\\1&-1&2&|&5\end{pmatrix}

Swapping to place the non-zero rows together and reducing R3→R3−R1R_3\to R_3-R_1: [1−1,−1−1,2−1 ∣ 5−6]=[0,−2,1 ∣ −1][1-1,-1-1,2-1\,|\,5-6]=[0,-2,1\,|\,-1], an independent non-zero row.

Only TWO genuinely independent, non-zero rows remain in both AA and [A∣B][A|B], so ρ(A)=ρ([A∣B])=2\rho(A)=\rho([A|B])=2. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.