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Mathematics · Ch 9 — Applications of Integration

Bernoulli's Formula

9.4

Bernoulli's Formula

The indefinite integral ∫u(x)v(x) dx\displaystyle\int u(x)v(x)\,dx of a product becomes especially simple to finish in one pass — instead of repeated integration by parts — when u(x)=a0xn+a1xn−1+⋯+anu(x)=a_0x^n+a_1x^{n-1}+\cdots+a_n is a polynomial and v(x)v(x) can be integrated over and over with ease (e.g. sin⁡nx,cos⁡nx,eax\sin nx,\cos nx,e^{ax}). The resulting shortcut is called Bernoulli's formula, an extension of ordinary integration by parts.

Notation. Write the successive derivatives of uu as

u(1)=dudx,u(2)=du(1)dx,u(3)=du(2)dx, …u^{(1)}=\dfrac{du}{dx},\quad u^{(2)}=\dfrac{du^{(1)}}{dx},\quad u^{(3)}=\dfrac{du^{(2)}}{dx},\ \ldots

and the successive anti-derivatives of vv as

v(1)=∫v dx,v(2)=∫v(1) dx,v(3)=∫v(2) dx, …v_{(1)}=\int v\,dx,\quad v_{(2)}=\int v_{(1)}\,dx,\quad v_{(3)}=\int v_{(2)}\,dx,\ \ldots

so that dv(1)=v dx, dv(2)=v(1) dx, dv(3)=v(2) dx,…dv_{(1)}=v\,dx,\ dv_{(2)}=v_{(1)}\,dx,\ dv_{(3)}=v_{(2)}\,dx,\ldots

Derivation. By integration by parts, ∫uv dx=∫u dv(1)=uv(1)−∫v(1) du=uv(1)−∫u(1)v(1) dx=uv(1)−∫u(1) dv(2)\int uv\,dx=\int u\,dv_{(1)}=uv_{(1)}-\int v_{(1)}\,du=uv_{(1)}-\int u^{(1)}v_{(1)}\,dx=uv_{(1)}-\int u^{(1)}\,dv_{(2)}. Applying by-parts again to the last integral: ∫u(1) dv(2)=u(1)v(2)−∫v(2) du(1)=u(1)v(2)−∫u(2)v(2) dx\int u^{(1)}\,dv_{(2)}=u^{(1)}v_{(2)}-\int v_{(2)}\,du^{(1)}=u^{(1)}v_{(2)}-\int u^{(2)}v_{(2)}\,dx. Substituting back and repeating this process gives

∫uv dx=uv(1)−u(1)v(2)+u(2)v(3)−u(3)v(4)+⋯\boxed{\int uv\,dx = uv_{(1)}-u^{(1)}v_{(2)}+u^{(2)}v_{(3)}-u^{(3)}v_{(4)}+\cdots}

called Bernoulli's formula for the integral of a product.

Note

Because uu is a polynomial of degree nn, its successive derivative u(n+1)u^{(n+1)} (and every derivative after it) is identically 00 — so the right-hand side is always a finite alternating sum with exactly n+1n+1 terms, never an infinite series. …