Exercise 12.1 · Q5
Q.(i) Define an operation on as follows: . Examine the closure, commutative, and associative properties satisfied by on .
(ii) Define an operation on as follows: . Examine the existence of identity and the existence of inverse for the operation on .
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Start your 14-day free trial to unlock the full solution →We check each property of directly against its definition, using one counterexample to disprove associativity and a general algebraic argument to rule out identity.
Step 1. Closure. For , and dividing by the nonzero rational keeps the result in . So always -- closed.
Step 2. Commutative. for all (ordinary addition is commutative) -- commutative.
Step 3. Associative -- test with a triple. Take .
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Since , for this triple -- not associative. …
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