Skip to content
Exercise 10.5 · Q3

Q.Find the equation of the curve whose slope is y−1x2+x\dfrac{y-1}{x^2+x} and which passes through the point (1,0)(1,0).

Tamil Nadu DgeTextbookSubjectiveImportance★★★★★
17% · 22/126 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Separate, split the xx-side into partial fractions, integrate both sides, then use the point (1,0)(1,0) to pin down the constant.

Step 1. Separate variables. dydx=y−1x2+x=y−1x(x+1) ⟹ dyy−1=dxx(x+1)\dfrac{dy}{dx}=\dfrac{y-1}{x^2+x}=\dfrac{y-1}{x(x+1)}\ \Longrightarrow\ \dfrac{dy}{y-1}=\dfrac{dx}{x(x+1)}.

Step 2. Partial fractions on the right. 1x(x+1)=1x−1x+1\dfrac{1}{x(x+1)}=\dfrac1x-\dfrac1{x+1}.

Step 3. Integrate both sides. ln⁡∣y−1∣=ln⁡∣x∣−ln⁡∣x+1∣+C=ln⁡∣xx+1∣+C\ln|y-1|=\ln|x|-\ln|x+1|+C=\ln\left|\dfrac{x}{x+1}\right|+C. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.