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Question 99 of 126

Q.If dydx=x−yx+y\dfrac{dy}{dx} = \dfrac{x - y}{x + y} then :

(a) x2+y2−2xy=cx^2 + y^2 - 2xy = c
(b) 2xy+y2+x2=c2xy + y^2 + x^2 = c
(c) x2−y2−2xy=cx^2 - y^2 - 2xy = c
(d) x2+y2−x+y=cx^2 + y^2 - x + y = c
Tamil Nadu DgeTamil Nadu HSC (DGE) Board 2018MCQ· 1mImportance★★★★★
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Treating dydx=x−yx+y\dfrac{dy}{dx}=\dfrac{x-y}{x+y} as an exact differential equation and integrating gives the solution x2−y2−2xy=cx^2-y^2-2xy=c.

  1. Cross-multiply: (x+y) dy=(x−y) dx(x+y)\,dy=(x-y)\,dx, i.e. (x−y) dx−(x+y) dy=0(x-y)\,dx-(x+y)\,dy=0.
  2. Identify M(x,y)=x−yM(x,y)=x-y and N(x,y)=−(x+y)=−x−yN(x,y)=-(x+y)=-x-y.
  3. Test exactness: ∂M∂y=−1\dfrac{\partial M}{\partial y}=-1 and ∂N∂x=−1\dfrac{\partial N}{\partial x}=-1. Since these are equal, the equation is exact.
  4. Find F(x,y)F(x,y) with ∂F∂x=M=x−y\dfrac{\partial F}{\partial x}=M=x-y: integrate with respect to xx: F=x22−xy+g(y)F=\dfrac{x^2}{2}-xy+g(y). …

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