From Concentration to Partial Pressure
So far, every equilibrium constant you have seen has been written using molar concentrations — the familiar square-bracket notation [A], with the constant called Kc. For reactions that involve gases, however, there is a more natural way to express the composition of the mixture: by using the partial pressure of each gas. The reason is simple: when you work with gases in a closed container, you measure pressure, not concentration. The equilibrium constant expressed in partial pressures is given the symbol Kp.
The bridge between concentration and pressure is the ideal gas law. For a gas:
Rearrange it:
p=VnRT
The quantity n/V is the concentration in moles per unit volume. If you measure concentration c in mol/L (or mol/dm3) and pressure p in bar, the relation becomes:
where R=0.0831 bar L mol−1K−1. You can also write this as p=[gas]RT, where [gas] is the molar concentration. At a fixed temperature, R and T are constants, so the pressure of a gas is directly proportional to its concentration:
p∝[gas]
This proportionality is the key that lets us convert between Kc and Kp.
The First Example: H2(g)+I2(g)⇌2HI(g)
For this reaction, you can write the equilibrium constant in two ways. Using concentrations:
Kc=[H2(g)][I2(g)][HI(g)]2
Using partial pressures:
Kp=(pH2)(pI2)(pHI)2
Now substitute p=[gas]RT for each gas:
Kp=([H2]RT)([I2]RT)([HI]RT)2=[H2][I2](RT)2[HI]2(RT)2=[H2][I2][HI]2=Kc
The (RT) factors cancel completely. For this particular reaction, Kp=Kc.
The cancellation happens because the number of moles of gaseous products equals the number of moles of gaseous reactants — two moles on each side. When that is true, the (RT) factors always cancel.
The Second Example: N2(g)+3H2(g)⇌2NH3(g)
Here the story is different. Write Kp:
Kp=(pN2)(pH2)3(pNH3)2
Substitute p=[gas]RT:
Kp=([N2]RT)([H2]RT)3([NH3]RT)2=[N2][H2]3(RT)4[NH3]2(RT)2=[N2][H2]3[NH3]2⋅(RT)−2
So:
Kp=Kc⋅(RT)−2
Or, more neatly:
Kp=Kc(RT)−2
The exponent −2 is not arbitrary. Count the moles of gas on each side:
- Products: 2 moles of NH3
- Reactants: 1+3=4 moles
- Difference: Δn=2−4=−2
That difference appears as the exponent of (RT).
The General Relation
For any gaseous reaction:
aA(g)+bB(g)⇌cC(g)+dD(g)
Write Kp:
Kp=(pA)a(pB)b(pC)c(pD)d
Substitute p=[gas]RT for every gas:
Kp=([A]RT)a([B]RT)b([C]RT)c([D]RT)d=[A]a[B]b[C]c[D]d⋅(RT)a+b(RT)c+d
The fraction of concentrations is exactly Kc. The exponent of (RT) is (c+d)−(a+b), which is the change in the number of moles of gas, Δn:
Δn=(moles of gaseous products)−(moles of gaseous reactants)
Kp=Kc(RT)Δn …