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Exercises · 5.19

Q.A mixture of dihydrogen and dioxygen at one bar pressure contains 20% by weight of dihydrogen. Calculate the partial pressure of dihydrogen.

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Step 1 – Assume a convenient total mass

Take 100 g of mixture: this contains 20 g H2_2 and 80 g O2_2 (20% by weight H2_2, as given).

Step 2 – Convert to moles

n(H2)=202=10 moln(\text{H}_2) = \frac{20}{2} = 10\ \text{mol}

n(O2)=8032=2.5 moln(\text{O}_2) = \frac{80}{32} = 2.5\ \text{mol}

Step 3 – Total moles and mole fraction of H2_2

ntotal=10+2.5=12.5 moln_{\text{total}} = 10+2.5 = 12.5\ \text{mol}

xH2=1012.5=0.8x_{\text{H}_2} = \frac{10}{12.5} = 0.8 …

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