Worked Examples · Example 11.3
Q.Boron is unable to form BF6^3– ion. Explain.
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Start your 14-day free trial to unlock the full solution →Step 1 - No d orbitals available
Boron's valence shell is ( only) - there are no orbitals in existence, so boron cannot expand its octet or use d orbitals for extra bonds the way heavier group 13/14 elements can.
Step 2 - Steric limitation
Even setting orbitals aside, boron's atomic/ionic radius is very small; six F atoms cannot be packed around such a small central atom without severe steric strain.
Step 3 - Contrast with aluminium …
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