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Q.Verify Rolle's theorem for the function y=f(x)=x2+4y = f(x) = x^{2} + 4 in [−3,3][-3, 3].

Telangana TsbieTelangana Board of Intermediate Education (Intermediate 1st Year) 2019Subjective· 2mImportance★★★★★
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Check the three conditions of Rolle's theorem (continuity, differentiability, equal end values), then solve f′(c)=0f'(c)=0.

Given f(x)=x2+4f(x) = x^{2}+4 on [−3,3][-3,3].

Condition 1 — Continuity on [−3,3][-3,3]: ff is a polynomial, so it is continuous everywhere, including [−3,3][-3,3]. ✓

Condition 2 — Differentiability on (−3,3)(-3,3): Polynomials are differentiable everywhere. ✓

Condition 3 — Equal end values:

f(−3)=(−3)2+4=9+4=13f(-3) = (-3)^{2}+4 = 9+4 = 13

f(3)=(3)2+4=9+4=13f(3) = (3)^{2}+4 = 9+4 = 13

Since f(−3)=f(3)=13f(-3)=f(3)=13. ✓

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