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Q.Define strictly increasing function and strictly decreasing function on an interval II.

Telangana TsbieTelangana Board of Intermediate Education (Intermediate 1st Year) 2020Subjective· 2mImportance★★★★★
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Concept understanding — Monotonic Function Analysis

Monotonic Function Analysis

A function is monotonic on an interval when it moves in a single direction across that interval — either always rising or always falling, never doubling back. Derivatives give us a clean, mechanical way to detect this, which is why monotonicity is one of the first applications of the derivative.

Increasing, Decreasing, Monotonic

On an interval II, a function ff is:

  • increasing if x1<x2⇒f(x1)≤f(x2)x_1 < x_2 \Rightarrow f(x_1) \le f(x_2),
  • strictly increasing if x1<x2⇒f(x1)<f(x2)x_1 < x_2 \Rightarrow f(x_1) < f(x_2),
  • decreasing if x1<x2⇒f(x1)≥f(x2)x_1 < x_2 \Rightarrow f(x_1) \ge f(x_2),
  • strictly decreasing if x1<x2⇒f(x1)>f(x2)x_1 < x_2 \Rightarrow f(x_1) > f(x_2).

A function that is either increasing throughout II or decreasing throughout II is called monotonic on II.

The Derivative Test

The slope of the tangent tells you the direction of travel. If ff is differentiable on an open interval II:

f′(x)>0 on I  ⟹  f is strictly increasing on If'(x) > 0 \text{ on } I \implies f \text{ is strictly increasing on } I

f′(x)<0 on I  ⟹  f is strictly decreasing on If'(x) < 0 \text{ on } I \implies f \text{ is strictly decreasing on } I

f′(x)=0 on I  ⟹  f is constant on If'(x) = 0 \text{ on } I \implies f \text{ is constant on } I

The idea is intuitive: a positive slope means the graph climbs as you move right, a negative slope means it falls.

How to Analyse Monotonicity

  1. Compute f′(x)f'(x).
  2. Solve f′(x)=0f'(x) = 0 (and note where f′f' is undefined). These critical points split the domain into intervals.
  3. Test the sign of f′f' in each interval.
  4. Read off where ff increases (f′>0f' > 0) and decreases (f′<0f' < 0).

Example. For f(x)=x2−4x+1f(x) = x^2 - 4x + 1, f′(x)=2x−4f'(x) = 2x - 4. So f′(x)<0f'(x) < 0 for x<2x < 2 and f′(x)>0f'(x) > 0 for x>2x > 2: the function decreases on (−∞,2)(-\infty, 2) and increases on (2,∞)(2, \infty). …

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