Q.Express cosh−1(45) in logarithmic form and hence find its value.
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Concept understanding — Logarithmic Forms of Inverse Hyperbolic Functions
Every inverse hyperbolic function can be rewritten as an explicit natural logarithm, and this is what makes the inverse functions computable rather than merely abstract symbols. The three principal theorems are:
sinh−1x=log(x+x2+1)for all real x,cosh−1x=log(x+x2−1)for x≥1,
tanh−1x=21log1−x1+xfor −1<x<1.
The proof strategy is identical in every case: set y equal to the inverse function, write x in terms of ey and e−y using the original definition, and multiply through by ey (or e2y) to turn the equation into a genuine quadratic in ey. Solving that quadratic, exactly one root is admissible (the other is rejected because ey must be positive, or because it lies outside the principal branch), and taking a logarithm of the surviving root recovers y.
For instance, for sinh−1x, writing x=sinhy=21(ey−e−y) gives e2y−2xey−1=0; the quadratic formula gives ey=x±x2+1, and since x2+1>∣x∣ always, only ey=x+x2+1 is positive for every real x — so no domain restriction is needed here, unlike for cosh−1x, where both roots of the corresponding quadratic are positive when x>1 and we must additionally insist on the branch y≥0 to pick x+x2−1 over its reciprocal x−x2−1.
These log-forms turn every "evaluate sinh−1(…)" or "solve coshx=…" problem into ordinary algebra: substitute the given number into the formula, simplify the surd, and (if a decimal is wanted) take the logarithm at the end — never before combining the terms inside it.
[!TLDR] Apply the log-form theorem cosh−1x=log(x+x2−1) with x=5/4.
[!ANSWER] cosh−1(45)=log2.
Step 1. The log-form theorem states cosh−1x=log(x+x2−1) for x≥1. Since 45≥1, it applies here.
Step 2. Compute x2−1=1625−1=169, so x2−1=43.
Step 3. Substitute into the formula: cosh−1(45)=log(45+43)=log(48)=log2.
[!ANSWER] cosh−1(45)=log2.
Using the sinh−1 log-form (with +1 under the surd) by mistake instead of the cosh−1 form (with −1).
Forgetting to check x≥1 before applying the formula, since cosh−1x is undefined for x<1.