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Exercise 9(a) · Q3

Q.Express cosh⁡−1(54)\cosh^{-1}\left(\dfrac{5}{4}\right) in logarithmic form and hence find its value.

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Step 1. The log-form theorem states cosh⁡−1x=log⁡(x+x2−1)\cosh^{-1}x = \log\left(x+\sqrt{x^2-1}\right) for x≥1x \geq 1. Since 54≥1\dfrac{5}{4} \geq 1, it applies here.

Step 2. Compute x2−1=2516−1=916x^2-1 = \dfrac{25}{16}-1 = \dfrac{9}{16}, so x2−1=34\sqrt{x^2-1} = \dfrac{3}{4}.

Step 3. Substitute into the formula: cosh⁡−1(54)=log⁡(54+34)=log⁡(84)=log⁡2\cosh^{-1}\left(\dfrac{5}{4}\right) = \log\left(\dfrac{5}{4}+\dfrac{3}{4}\right) = \log\left(\dfrac{8}{4}\right) = \log 2.

[!ANSWER] cosh⁡−1(54)=log⁡2\cosh^{-1}\left(\dfrac{5}{4}\right) = \log 2.

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