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Q.If f={(4,5),(5,6),(6,−4)}f = \{(4,5), (5,6), (6,-4)\} and g={(4,−4),(6,5),(8,5)}g = \{(4,-4), (6,5), (8,5)\}, then find i) f+gf+g ii) f−gf-g iii) 2f+4g2f+4g iv) f+4f+4 v) fgfg vi) f/gf/g vii) ∣f∣|f|.

Telangana TsbieTelangana Board of Intermediate Education (Intermediate 1st Year) 2022Subjective· 7mImportance★★★★★
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Domain of f={4,5,6}f=\{4,5,6\}, domain of g={4,6,8}g=\{4,6,8\}. Every combined operation (f±gf\pm g, fgfg, f/gf/g, linear combinations of both) is defined only on the common domain {4,6}\{4,6\}; operations involving only ff (adding a constant, or ∣f∣|f|) use ff's own domain {4,5,6}\{4,5,6\}.

From the given sets, read off the function values:

f(4)=5, f(5)=6, f(6)=−4g(4)=−4, g(6)=5, g(8)=5f(4)=5,\ f(5)=6,\ f(6)=-4 \qquad g(4)=-4,\ g(6)=5,\ g(8)=5

Any operation combining ff and gg (sum, difference, product, quotient, or a linear combination like 2f+4g2f+4g) needs BOTH functions defined, so its domain is dom(f)∩dom(g)={4,5,6}∩{4,6,8}={4,6}\text{dom}(f)\cap\text{dom}(g) = \{4,5,6\}\cap\{4,6,8\} = \{4,6\}.

i) f+gf+g on {4,6}\{4,6\}:

(f+g)(4)=5+(−4)=1(f+g)(4) = 5+(-4) = 1, (f+g)(6)=−4+5=1(f+g)(6) = -4+5 = 1

f+g={(4,1),(6,1)}f+g = \{(4,1),(6,1)\}

ii) f−gf-g on {4,6}\{4,6\}:

(f−g)(4)=5−(−4)=9(f-g)(4) = 5-(-4) = 9, (f−g)(6)=−4−5=−9(f-g)(6) = -4-5 = -9

f−g={(4,9),(6,−9)}f-g = \{(4,9),(6,-9)\}

iii) 2f+4g2f+4g on {4,6}\{4,6\}:

(2f+4g)(4)=2(5)+4(−4)=10−16=−6(2f+4g)(4) = 2(5)+4(-4) = 10-16 = -6

(2f+4g)(6)=2(−4)+4(5)=−8+20=12(2f+4g)(6) = 2(-4)+4(5) = -8+20 = 12

2f+4g={(4,−6),(6,12)}2f+4g = \{(4,-6),(6,12)\}

iv) f+4f+4 (adding the constant 4, so it only needs ff; domain stays {4,5,6}\{4,5,6\}):

(f+4)(4)=5+4=9(f+4)(4)=5+4=9, (f+4)(5)=6+4=10(f+4)(5)=6+4=10, (f+4)(6)=−4+4=0(f+4)(6)=-4+4=0

f+4={(4,9),(5,10),(6,0)}f+4 = \{(4,9),(5,10),(6,0)\}

v) fgfg on {4,6}\{4,6\}:

(fg)(4)=5×(−4)=−20(fg)(4) = 5\times(-4) = -20, (fg)(6)=−4×5=−20(fg)(6) = -4\times 5 = -20

fg={(4,−20),(6,−20)}fg = \{(4,-20),(6,-20)\}

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