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Q.Find the fourth vertex of the parallelogram whose consecutive vertices are (2,4,−1)(2, 4, -1), (3,6,−1)(3, 6, -1) and (4,5,1)(4, 5, 1).

Telangana TsbieTelangana Board of Intermediate Education (Intermediate 1st Year) 2024Subjective· 2mImportance★★★★★
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In a parallelogram the diagonals bisect each other, so the fourth vertex can be found from OD⃗=OA⃗+OC⃗−OB⃗\vec{OD}=\vec{OA}+\vec{OC}-\vec{OB} (equivalently, the midpoint of one diagonal equals the midpoint of the other).

Let A(2,4,−1)A(2,4,-1), B(3,6,−1)B(3,6,-1), C(4,5,1)C(4,5,1) be consecutive vertices of parallelogram ABCDABCD, and D(x,y,z)D(x,y,z) the vertex to find.

Since AB∥DCAB \parallel DC and AB=DCAB = DC as vectors (opposite sides of a parallelogram):

AB⃗=DC⃗  ⟹  D=A+C−B\vec{AB} = \vec{DC} \implies D = A + C - B

x=2+4−3=3,y=4+5−6=3,z=−1+1−(−1)=1x = 2+4-3 = 3,\quad y = 4+5-6 = 3,\quad z = -1+1-(-1) = 1

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