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Physics · Ch 10 — Mechanical Properties of Fluids

Stokes' Law

10.5.1

Stokes' Law

Viscosity and Stokes' Law

When a solid object moves through a fluid, the fluid exerts a resistive force that opposes the motion. This force arises from viscosity — the internal friction between layers of the fluid. For a small sphere moving slowly through a viscous fluid, this resistive force takes a particularly simple form.

The Origin of the Viscous Drag

Consider a sphere of radius rr moving with a constant velocity vv through a fluid of viscosity η\eta. The fluid layers in contact with the sphere's surface are dragged along, while layers farther away are at rest. This velocity gradient creates shear stresses that produce a net retarding force on the sphere.

The exact calculation of this force requires solving the Navier-Stokes equations of fluid dynamics — a complex mathematical problem. However, for the special case of slow, steady motion (where inertial forces are negligible compared to viscous forces), the British physicist George Gabriel Stokes derived a remarkably simple result.

Stokes' Law

F=6πηrvF = 6 \pi \eta r v

The viscous drag force FF on a sphere moving through a fluid is directly proportional to:

  • The viscosity η\eta of the fluid
  • The radius rr of the sphere
  • The velocity vv of the sphere

The constant of proportionality is 6π6\pi, making the complete expression F=6πηrvF = 6\pi\eta r v.

Watch out

Stokes' law applies only under these conditions:

  • The fluid is incompressible and Newtonian (viscosity constant)
  • The flow is laminar (streamlined), not turbulent
  • The sphere moves at a constant velocity (terminal velocity)
  • The Reynolds number is less than about 0.1 (very slow flow)
  • The fluid extends infinitely in all directions (no wall effects)

Terminal Velocity of a Falling Sphere

When a sphere is released in a viscous fluid, three forces act on it:

  1. Weight acting downward: W=mg=43πr3ρgW = mg = \frac{4}{3}\pi r^3 \rho g, where ρ\rho is the density of the sphere material
  2. Buoyant force acting upward: Fb=43πr3σgF_b = \frac{4}{3}\pi r^3 \sigma g, where σ\sigma is the density of the fluid
  3. Viscous drag acting upward: Fd=6πηrvF_d = 6\pi\eta r v

Initially, the sphere accelerates downward because its weight exceeds the sum of buoyancy and drag. As velocity increases, the drag force grows proportionally. Eventually, the net force becomes zero and the sphere continues with constant velocity — the terminal velocity.

At terminal velocity vtv_t:

Net force=0\text{Net force} = 0

43πr3ρg−43πr3σg−6πηrvt=0\frac{4}{3}\pi r^3 \rho g - \frac{4}{3}\pi r^3 \sigma g - 6\pi\eta r v_t = 0

43πr3(ρ−σ)g=6πηrvt\frac{4}{3}\pi r^3 (\rho - \sigma)g = 6\pi\eta r v_t

Solving for vtv_t:

vt=29r2(ρ−σ)gηv_t = \frac{2}{9} \frac{r^2 (\rho - \sigma)g}{\eta}

This is the terminal velocity of a sphere falling through a viscous fluid under gravity.

Important

Terminal velocity is proportional to the square of the radius. A sphere twice as large falls four times faster at terminal velocity. This is why large raindrops fall faster than small ones, and why tiny dust particles settle extremely slowly.

Applications of Stokes' Law

Determining viscosity: By measuring the terminal velocity of a small sphere falling through a fluid of known density, the viscosity can be calculated using Stokes' law. This is the principle behind the falling-sphere viscometer.

Sedimentation: The settling of particles in liquids (sedimentation) follows Stokes' law. This is used in:

  • Purifying water by allowing suspended particles to settle
  • Separating minerals in ore processing
  • Understanding the deposition of sediments in rivers and oceans

Motion of microorganisms: Many bacteria and single-celled organisms live in the low-Reynolds-number regime where Stokes' law applies. Their swimming mechanisms are fundamentally different from those of larger organisms because viscous forces dominate. …