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Q.Define angular velocity (omega). Derive V = r x omega.

Telangana TsbieTelangana Board of Intermediate Education (Intermediate 1st Year) 2022Subjective· 4mImportance★★★★★
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Angular velocity measures how fast the angular position changes with time; combining it with the position vector through a cross product gives the particle's linear velocity, V = ω × r.

Angular velocity. Consider a particle P moving on a circular path of radius r about a fixed axis through centre O. Let its angular position at time t be θ, measured from a fixed reference line. In a small time interval dt, the particle sweeps through a small angle dθ.

The angular velocity is defined as the time rate of change of angular displacement:

ω=dθdt\omega = \frac{d\theta}{dt}

Its SI unit is rad s⁻¹. Angular velocity is a vector quantity — its direction is along the axis of rotation, given by the right-hand rule (curl the fingers of the right hand in the sense of rotation; the thumb points along ω).

Derivation of V = r × ω (equivalently V = ω × r).

Let r be the position vector of the particle P drawn from a point O on the axis of rotation to P. As the particle rotates, in time dt it moves through an angle dθ and traces a small arc of length

ds=r dθds = r\,d\theta

(since arc length = radius × angle, for small dθ).

Dividing both sides by dt:

dsdt=rdθdt\frac{ds}{dt} = r\frac{d\theta}{dt}

v=rωv = r\omega

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