Q.State and prove law of conservation of energy in case of a freely falling body. A pump is required to lift 600 kg of water per minute from a well of 25 m deep and to eject it with a speed of 50 ms^-1. Calculate the power required to perform the above task.
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Start your 14-day free trial to unlock the full solution →For a freely falling body, KE gained equals PE lost at every point, so total mechanical energy stays constant. For the pump, power = mass flow rate × (energy given to the water per unit mass, from both lifting it and giving it speed) = 14.95 kW.
Part 1 — Conservation of energy for a freely falling body:
Consider a body of mass dropped from height above the ground, at a point where it has fallen a distance (so it is at height above the ground) and has speed .
Using (from kinematics, starting from rest):
Potential energy at that point (taking the ground as reference):
Total mechanical energy at that point:
This is exactly the total energy the body had at the start (all PE, since there): .
Since at every point during the fall (independent of ), the total mechanical energy remains constant throughout the fall — this proves conservation of energy for a freely falling body: PE lost = KE gained, at every instant.
Part 2 — Power required by the pump:
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