Q.State and prove Law of Conservation of Energy in case of a freely falling body.
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Start your 14-day free trial to unlock the full solution →The law of conservation of energy says total energy is constant (only transformed). For a body falling freely from height H, KE + PE = mgH at the top, midway and at the ground - proving mechanical energy is conserved as PE turns into KE.
Law of conservation of energy: Energy can neither be created nor destroyed. It can only be transformed from one form to another, and the total energy of an isolated system always remains constant.
Proof for a freely falling body:
Consider a body of mass m released from rest from a height H above the ground. Let g be the acceleration due to gravity. We find the total mechanical energy (KE + PE) at three points, measuring height from the ground.
(A) At the highest point (height H):
- Velocity = 0, so kinetic energy KE = 0.
- Potential energy PE = mgH.
- Total energy E = 0 + mgH = mgH.
(B) After falling a distance x (at height H - x):
- Using v^2 = u^2 + 2ax with u = 0, a = g, distance = x: v^2 = 2gx.
- Kinetic energy KE = (1/2) m v^2 = (1/2) m (2gx) = mgx.
- Potential energy PE = mg(H - x).
- Total energy E = mgx + mg(H - x) = mgH.
(C) At the ground (height 0, having fallen the full height H):
- Using v^2 = 2gH: KE = (1/2) m (2gH) = mgH.
- Potential energy PE = 0. …
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