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Q.Explain the following reactions with equations.

a) Kolbe's reaction
b) Riemer - Tiemann reaction
c) Williamson's ether synthesis
d) HVZ reaction
Telangana TsbieTelangana Board of Intermediate Education 2018Subjective· 8mImportance★★★★★
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These four named reactions build C–C, C–O, and C–X bonds at specific positions in phenols, ethers, and carboxylic acids using characteristic reagents.

a) Kolbe's reaction:

Sodium phenoxide (formed by treating phenol with NaOH) is heated with carbon dioxide at about 400 K under a pressure of 4–7 atmospheres. The CO2CO_2 electrophile attacks the ortho position of the phenoxide ring (favoured due to the chelation/ionic character of the intermediate), and the resulting product is acidified to give salicylic acid (2-hydroxybenzoic acid):

C6H5ONa+CO2→400 K, 4−7 atmsodium salicylate→H+o-HOC6H4COOHsalicylic acidC_6H_5ONa + CO_2 \xrightarrow{400\,K,\ 4-7\,atm} \text{sodium salicylate} \xrightarrow{H^+} \underset{\text{salicylic acid}}{o\text{-}HOC_6H_4COOH}

b) Riemer–Tiemann reaction:

When phenol is treated with chloroform (CHCl3CHCl_3) and concentrated sodium hydroxide (NaOH) at 340 K, dichlorocarbene (:CCl2:CCl_2), generated from CHCl3 and NaOH, attacks the electron-rich ortho position of the phenoxide ring. Subsequent hydrolysis of the intermediate (a gem-dichloride) gives an ortho-hydroxybenzaldehyde called salicylaldehyde:

C6H5OH→CHCl3, NaOH(dichlorocarbene attack at ortho)→H3O+o-HOC6H4CHOsalicylaldehydeC_6H_5OH \xrightarrow{CHCl_3,\ NaOH} \text{(dichlorocarbene attack at ortho)} \xrightarrow{H_3O^+} \underset{\text{salicylaldehyde}}{o\text{-}HOC_6H_4CHO}

c) Williamson's ether synthesis:

An alkyl halide is treated with sodium alkoxide (prepared by reacting an alcohol with sodium metal). The alkoxide ion acts as a nucleophile and attacks the alkyl halide in an SN2 reaction, displacing the halide ion and forming an ether:

R−O−Na++R′−X→R−O−R′+NaXR-O^-Na^+ + R'-X \rightarrow R-O-R' + NaX

(For best yield, a primary alkyl halide is used, since a bulky/secondary or tertiary halide favours elimination instead of substitution.)

d) HVZ (Hell–Volhard–Zelinsky) reaction: …

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