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Q.If x=cis⁡θx = \operatorname{cis}\theta, then find the value of (x6+1x6)\left(x^6 + \dfrac{1}{x^6}\right).

Telangana TsbieTelangana Board of Intermediate Education 2023Subjective· 2mImportance★★★★★
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x6+1x6=2cos⁡6θx^6 + \dfrac{1}{x^6} = 2\cos 6\theta.

Here x=cis⁡θ=cos⁡θ+isin⁡θx = \operatorname{cis}\theta = \cos\theta + i\sin\theta. By De Moivre's theorem,

x6=cis⁡6θ=cos⁡6θ+isin⁡6θx^6 = \operatorname{cis} 6\theta = \cos 6\theta + i\sin 6\theta,

1x6=x−6=cis⁡(−6θ)=cos⁡6θ−isin⁡6θ\dfrac{1}{x^6} = x^{-6} = \operatorname{cis}(-6\theta) = \cos 6\theta - i\sin 6\theta.

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