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Q.If A, B, C are angles of a triangle such that x=Cis Ax = \text{Cis } A, y=Cis By = \text{Cis } B, z=Cis Cz = \text{Cis } C, then find the value of xyzxyz.

Telangana TsbieTelangana Board of Intermediate Education 2025Subjective· 2mImportance★★★★★
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xyz=Cis(A+B+C)=Cis π=−1xyz=\text{Cis}(A+B+C)=\text{Cis}\,\pi=-1 because A+B+C=πA+B+C=\pi in a triangle.

Recall Cis θ=cos⁡θ+isin⁡θ\text{Cis}\,\theta=\cos\theta+i\sin\theta, and the product rule

Cis A⋅Cis B⋅Cis C=Cis(A+B+C).\text{Cis}\,A\cdot\text{Cis}\,B\cdot\text{Cis}\,C=\text{Cis}(A+B+C).

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