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Exercise 7(a) · Q4

Q.Resolve x2+x+1(x−1)2(x+2)\dfrac{x^2+x+1}{(x-1)^2(x+2)} into partial fractions.

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Step 1. Write

x2+x+1(x−1)2(x+2)=Ax−1+B(x−1)2+Cx+2.\frac{x^2+x+1}{(x-1)^2(x+2)}=\frac A{x-1}+\frac B{(x-1)^2}+\frac C{x+2}.

Step 2. Clear denominators:

x2+x+1=A(x−1)(x+2)+B(x+2)+C(x−1)2.x^2+x+1=A(x-1)(x+2)+B(x+2)+C(x-1)^2.

Step 3. Substitute x=1x=1: 1+1+1=B(3) ⇒ 3=3B ⇒ B=11+1+1=B(3)\ \Rightarrow\ 3=3B\ \Rightarrow\ B=1.

Step 4. Substitute x=−2x=-2: 4−2+1=C(9) ⇒ 3=9C ⇒ C=134-2+1=C(9)\ \Rightarrow\ 3=9C\ \Rightarrow\ C=\dfrac13. …

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