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Exercise 4(a) · Q8

Q.Form the monic cubic equation with rational coefficients, two of whose roots are 2+32+\sqrt3 and 2−32-\sqrt3, the third root being 11.

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Step 1. The conjugate pair 2+3, 2−32+\sqrt3,\ 2-\sqrt3 combines to the rational quadratic factor

(x−(2+3))(x−(2−3))=(x−2)2−3=x2−4x+4−3=x2−4x+1.\big(x-(2+\sqrt3)\big)\big(x-(2-\sqrt3)\big)=(x-2)^2-3=x^2-4x+4-3=x^2-4x+1.

Step 2. The required cubic is (x2−4x+1)(x−1)=0(x^2-4x+1)(x-1)=0.

Step 3. Expand:

(x2−4x+1)(x−1)=x3−4x2+x−x2+4x−1=x3−5x2+5x−1.(x^2-4x+1)(x-1)=x^3-4x^2+x-x^2+4x-1=x^3-5x^2+5x-1. …

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