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Q.If the product of roots of 4x3+16x2−9x−a=04x^3 + 16x^2 - 9x - a = 0 is 9, then find aa.

Telangana TsbieTelangana Board of Intermediate Education 2019Subjective· 2mImportance★★★★★
69% · 25/36 Questions
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For a cubic px3+qx2+rx+s=0px^3+qx^2+rx+s=0, the product of the roots is −s/p-s/p; set this equal to 9 and solve for aa.

Given 4x3+16x2−9x−a=04x^3+16x^2-9x-a = 0, so p=4p=4, q=16q=16, r=−9r=-9, s=−as=-a.

Product of roots =−sp=−−a4=a4= -\dfrac{s}{p} = -\dfrac{-a}{4} = \dfrac{a}{4}. …

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