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Physics · Ch 8 — Magnetism and Matter

The Dipole in a Uniform Magnetic Field

8.2.3

The Dipole in a Uniform Magnetic Field

Torque on a Magnetic Dipole in a Uniform Field

When a magnetic dipole (like a compass needle) of magnetic moment m\mathbf{m} is placed in a uniform magnetic field B\mathbf{B}, it experiences a torque. This torque tends to rotate the dipole to align it with the field.

The torque τ\boldsymbol{\tau} is given by the cross product:

τ=m×B\boldsymbol{\tau} = \mathbf{m} \times \mathbf{B}

In magnitude, this is:

τ=mBsin⁡θ\tau = mB \sin\theta

where:

  • mm is the magnitude of the magnetic moment,
  • BB is the magnitude of the uniform magnetic field,
  • θ\theta is the angle between m\mathbf{m} and B\mathbf{B}.

This torque is a restoring torque — it always acts to bring the dipole towards θ=0∘\theta = 0^\circ (alignment with the field).

Magnetic Potential Energy

The magnetic potential energy UmU_m of the dipole in the field is defined as the work done by an external agent to rotate the dipole from a reference orientation to a given angle θ\theta.

Starting from the torque expression, the work done (and hence the change in potential energy) for an infinitesimal angular displacement dθd\theta is:

dUm=τ dθ=mBsin⁡θ dθdU_m = \tau \, d\theta = mB \sin\theta \, d\theta

Integrating from a reference angle θ0\theta_0 to θ\theta:

Um(θ)−Um(θ0)=∫θ0θmBsin⁡θ′ dθ′=mB(−cos⁡θ+cos⁡θ0)U_m(\theta) - U_m(\theta_0) = \int_{\theta_0}^{\theta} mB \sin\theta' \, d\theta' = mB (-\cos\theta + \cos\theta_0)

Choosing the zero of potential energy at θ0=90∘\theta_0 = 90^\circ (when the dipole is perpendicular to the field), we set Um(90∘)=0U_m(90^\circ) = 0. Then cos⁡θ0=cos⁡90∘=0\cos\theta_0 = \cos 90^\circ = 0, giving:

Um(θ)=−mBcos⁡θU_m(\theta) = -mB \cos\theta

This can be written compactly as the dot product:

Um=−m⋅BU_m = -\mathbf{m} \cdot \mathbf{B}

Interpretation of Potential Energy …