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Worked Examples · Example 4
Q.

Calculate the average marks of the following students using (a) Direct method and (b) Step deviation method.

Marks0-1010-2020-3030-4040-5050-6060-70
No. of Students5121525832
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For a continuous series the mean is found from class mid-points. The direct method uses Xˉ=∑fmN\bar{X}=\frac{\sum fm}{N} and the step-deviation method takes an assumed mean (A = 35) with common factor c = 10. Both give the same answer, about 30.14 marks.

Concept

For grouped data:

  • Direct method: Xˉ=∑fm∑f\bar{X} = \dfrac{\sum fm}{\sum f}, where mm is the mid-point of each class.
  • Step-deviation method: Xˉ=A+∑fd′∑f×c\bar{X} = A + \dfrac{\sum fd'}{\sum f}\times c, where d′=m−Acd' = \dfrac{m-A}{c}, AA = assumed mean, cc = class width.

(a) Direct method

Marksffmid mmfmfm
0–105525
10–201215180
20–301525375
30–402535875
40–50845360
50–60355165
60–70265130
Total702110

Xˉ=∑fmN=211070=30.14\bar{X} = \frac{\sum fm}{N} = \frac{2110}{70} = 30.14

(b) Step-deviation method

Take A=35A = 35, c=10c = 10, d′=m−3510d' = \dfrac{m-35}{10}.

| mm | ff | d′d' | fd′fd' |

|---|---|---|---| …

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