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NCERT Exemplar · Q23

Q.On a number line, an open (unfilled) circle is drawn at x=72x=\dfrac{7}{2}, and the line is shaded as a ray beginning just to the left of 72\dfrac{7}{2} and extending indefinitely toward −∞-\infty. The point 72\dfrac{7}{2} is not included. Which interval represents this solution set?
(A) x∈(−∞,72)x \in \left(-\infty, \dfrac{7}{2}\right)
(B) x∈(−∞,72]x \in \left(-\infty, \dfrac{7}{2}\right]
(C) x∈[72,−∞)x \in \left[\dfrac{7}{2}, -\infty\right)
(D) x∈(72,∞)x \in \left(\dfrac{7}{2}, \infty\right)

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The shading covers every point to the left of 72\dfrac{7}{2}, and the open circle shows 72\dfrac{7}{2} is excluded. Hence x<72x < \dfrac{7}{2}, i.e. (−∞,72)\left(-\infty, \dfrac{7}{2}\right).

Concept

A ray toward −∞-\infty means "xx less than the marked value"; an open circle marks a strict inequality (endpoint excluded).

Steps

  1. Direction: toward −∞-\infty ⇒\Rightarrow x<72x < \dfrac{7}{2} (or ≤\le).
  2. Endpoint: open circle ⇒\Rightarrow strict ⇒\Rightarrow x<72x < \dfrac{7}{2}.
  3. Interval form: (−∞,72)\left(-\infty, \dfrac{7}{2}\right).

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