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Exercise 5.1 · Q11

Q.3(x−2)5≤5(2−x)3\dfrac{3(x - 2)}{5} \le \dfrac{5(2 - x)}{3}

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Multiply through by 1515, expand, collect like terms, and isolate xx. The solution is x≤2x \le 2, i.e. (−∞,2](-\infty, 2].

The fractions are cleared first by multiplying by the LCM of 55 and 33, which is 1515. Since 15>015 > 0, the inequality direction is preserved.

Step-by-step solution

  1. Clear the denominators. Multiply both sides by 1515:

15⋅3(x−2)5≤15⋅5(2−x)315\cdot\frac{3(x-2)}{5} \le 15\cdot\frac{5(2-x)}{3}

9(x−2)≤25(2−x)9(x-2) \le 25(2-x)

  1. Expand both sides.

9x−18≤50−25x9x - 18 \le 50 - 25x

  1. Collect xx-terms. Add 25x25x to both sides:

34x−18≤5034x - 18 \le 50

  1. Isolate the xx-term. Add 1818: 34x≤6834x \le 68 …

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