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NCERT Exemplar · Q1

Q.The number of significant figures in 0.06900 is

(a) 5
(b) 4
(c) 2
(d) 3
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✓ Free question

Zeros after a decimal point that follow a non-zero digit and trail the number are significant when they indicate measurement precision. The answer is 4 significant figures.

Understanding Significant Figures

Significant figures tell us about the precision of a measurement. They represent all the digits we are confident about, plus one uncertain digit. The challenge with zeros is knowing when they're placeholders (showing scale) versus when they carry information about precision.

The rules crystallize around one principle: trailing zeros after the decimal point, following a non-zero digit, are always significant because you wouldn't write them unless your measuring instrument justified that precision.

Analyzing 0.06900

Let me walk through this number digit by digit:

  1. The leading zero before the decimal (0.) is never significant. It's just notation—we could write this as .06900 in some contexts. This zero tells us nothing about measurement precision.

  2. The zero immediately after the decimal (0.0...) is also not significant. It's a placeholder showing that our number is in the hundredths range or smaller. If we expressed this in scientific notation as 6.900×10−26.900 \times 10^{-2}, this zero would disappear entirely.

  3. The digit 6 is our first non-zero digit. This is significant—it's the first digit that carries actual measurement information.

  4. The digit 9 is significant. Any non-zero digit is always significant.

  5. The first trailing zero (0.0690_) is significant. Once we've started counting significant figures after a non-zero digit, all subsequent digits matter.

  6. The final trailing zero (0.06900) is also significant. This is the key insight: you wrote this zero deliberately to show your measurement was precise to five decimal places. If your instrument only measured to 0.0690.069, you would have stopped there.

Tip

In scientific notation, significant figures become obvious: 0.06900=6.900×10−20.06900 = 6.900 \times 10^{-2} clearly shows four significant figures (6, 9, 0, 0).

Watch out

Students often mistakenly count all zeros, giving 5, or ignore all zeros, giving 2. The rule is: leading zeros never count; trailing zeros after the decimal do count when they follow a non-zero digit.

Counting our significant figures: 6, 9, 0, 0 gives us four significant figures total.

✓Final answer

The correct option is (B) 4.

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