Q.Which of the following species is not expected to be a ligand?
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Coordination Compound Nomenclature: From Intuition to Precision
Imagine you're naming a person. You'd say "Ravi Sharma" — family name first, then given name. Coordination compounds have a similar logic, but the "family name" is the metal, and the "given names" are the groups attached to it. The rules are just a systematic way of writing that name so any chemist anywhere can draw the exact structure from it.
The Core Idea
A coordination compound has a central metal ion surrounded by molecules or ions called ligands. Think of the metal as the nucleus and ligands as planets orbiting it. The entire assembly (metal + ligands) is called the coordination sphere, and it's written inside square brackets: [Co(NH₃)₆]Cl₃.
The nomenclature rules tell you:
- What order to list things
- How to name each ligand
- How to indicate the metal's oxidation state
- How to handle the counter-ions outside the brackets
The Rules, Step by Step
1. Cation before anion (just like NaCl is sodium chloride)
If the complex ion is positive, it's named first. If it's negative, it's named last. Simple.
2. Within the coordination sphere: ligands first, then metal
This is the big rule. Ligands are named before the metal, in alphabetical order (ignoring prefixes like di-, tri-).
Alphabetical order is based on the ligand's name, not its formula. So NH₃ (ammine) comes before H₂O (aqua), even though N comes after H in the alphabet.
3. Naming ligands
| Ligand type | Name | Example |
|---|---|---|
| Neutral molecule (NH₃) | ammine | [Co(NH₃)₆]³⁺ → hexaamminecobalt(III) |
| Neutral molecule (H₂O) | aqua | [Cu(H₂O)₄]²⁺ → tetraaquacopper(II) |
| Neutral molecule (CO) | carbonyl | [Ni(CO)₄] → tetracarbonylnickel(0) |
| Negative ion (Cl⁻) | chloro | [PtCl₆]²⁻ → hexachloroplatinate(IV) |
| Negative ion (CN⁻) | cyano | [Fe(CN)₆]⁴⁻ → hexacyanoferrate(II) |
| Negative ion (OH⁻) | hydroxo | [Al(OH)₄]⁻ → tetrahydroxoaluminate(III) |
ammine (with two m's) is for NH₃ as a ligand. amine (one m) is for organic compounds like ethylamine. Don't mix them up — exam setters love this trap.
4. Prefixes for multiple ligands
Use Greek prefixes: di-, tri-, tetra-, penta-, hexa-, hepta-, octa-.
If the ligand name already contains a number (like ethylenediamine), use bis-, tris-, tetrakis- instead.
[Co(en)₃]³⁺ is tris(ethylenediamine)cobalt(III), not triethylenediaminecobalt(III). The parentheses around the ligand name are mandatory when using bis/tris/tetrakis.
5. Oxidation state of the metal
Write it in Roman numerals in parentheses right after the metal name. No space.
[Fe(CN)₆]³⁻ → hexacyanoferrate(III) (iron is in +3 state)
6. If the complex is an anion, change the metal's ending
| Metal | Anionic form |
|---|---|
| Cobalt | cobaltate |
| Copper | cuprate |
| Iron | ferrate |
| Nickel | nickelate |
| Platinum | platinate |
| Zinc | zincate |
General pattern:
[M(L)ₙ]Xₘ → cation name = [prefix-ligands]metal(oxidation state)
anion name = [prefix-ligands]metalate(oxidation state)
Worked Examples
Example 1: K₃[Fe(CN)₆]
- Cation: potassium (K⁺)
- Complex anion:
[Fe(CN)₆]³⁻ - Ligands: 6 cyano → hexacyano
- Metal: iron → ferrate (because it's an anion)
- Oxidation state: Fe is +3 (since 6 CN⁻ = -6, total charge -3, so Fe must be +3)
- Answer: Potassium hexacyanoferrate(III)
Example 2: [Co(NH₃)₅Cl]Cl₂
- Cation:
[Co(NH₃)₅Cl]²⁺ - Ligands: 5 ammine + 1 chloro → alphabetical: ammine before chloro → pentaamminechloro
- Metal: cobalt
- Oxidation state: Co is +3 (5 NH₃ neutral, 1 Cl⁻ = -1, total +2, so Co = +3) …
Why this formula?
Coordination Compound Nomenclature: Why the Rules Work
Coordination compound nomenclature isn't about a single formula — it's a system of rules built on a few core principles. Let's understand the why behind each major rule, so you never have to memorise blindly.
1. The Central Idea: Ligands as "Guests" Around a Metal "Host"
A coordination compound has a central metal atom/ion surrounded by ligands (molecules or ions that donate electron pairs). The naming reflects this relationship:
- Cation first, then anion (like normal ionic compounds)
- Ligands named before the metal (because they modify the metal's identity)
Why?
In chemistry, we name the more electropositive part first (cation). The metal-ligand complex is treated as a single unit — the ligands are "attached" to the metal, so they come first in the complex name.
2. Key Rule: Ligand Order — Alphabetical, Not by Charge
Rule: Ligands are named in alphabetical order (ignoring prefixes like di-, tri-).
Why?
- If we ordered by charge or size, the name would change every time a ligand is replaced.
- Alphabetical order is universal and unambiguous — it doesn't depend on the metal or oxidation state.
- Example:
[Co(NH₃)₄Cl₂]⁺is tetraamminedichlorocobalt(III) — "ammine" (a) before "chloro" (c).
3. Oxidation State: Why Roman Numerals?
Rule: The metal's oxidation state is written in Roman numerals in parentheses after the metal name.
Why?
- The oxidation state tells you the charge on the metal after accounting for ligand charges.
- Roman numerals avoid confusion with Arabic numbers (which are used for ligand counts).
- Example:
[Fe(CN)₆]³⁻→ hexacyanoferrate(III) — the iron is Fe³⁺, not Fe²⁺.
Derivation of oxidation state:
Let the complex charge = Q, ligand charges = sum of ligand charges L, number of ligands = n.
Then:
Metal oxidation state=Q−L
For [Fe(CN)₆]³⁻: CN⁻ has charge -1, so L=6×(−1)=−6, Q=−3.
Fe oxidation state=−3−(−6)=+3
4. Anionic Ligands: The "-o" Ending
Rule: Anionic ligands (negative ions) end in -o (e.g., Cl⁻ → chloro, CN⁻ → cyano, OH⁻ → hydroxo).
Why?
- This distinguishes them from neutral ligands (e.g., NH₃ → ammine, H₂O → aqua).
- The suffix -o signals "this ligand came from an anion" — crucial for charge balance.
Common examples:
| Anion | Ligand name |
|---|---|
| Cl⁻ | chloro |
| CN⁻ | cyano |
| OH⁻ | hydroxo |
| SO₄²⁻ | sulfato |
5. Neutral Ligands: Special Names
Rule: Neutral ligands keep their molecular name, except for a few with special names:
- NH₃ → ammine (not "ammonia")
- H₂O → aqua
- CO → carbonyl
- NO → nitrosyl
Why?
- "Ammine" avoids confusion with ammonia (NH₃) as a free molecule.
- These special names are historical but standardised — you must memorise them for exams.
6. Prefixes: di-, tri-, tetra-, etc.
Rule: Use Greek prefixes to indicate the number of each ligand:
- 2 → di, 3 → tri, 4 → tetra, 5 → penta, 6 → hexa
Why?
- Without prefixes,
[Co(NH₃)₆]³⁺would be "hexaamminecobalt(III)" — the "hexa" tells you there are six ammines. - For ligands with complex names (e.g., ethylenediamine), use bis-, tris-, tetrakis- to avoid confusion.
Example:
[Co(en)₃]³⁺ → tris(ethylenediamine)cobalt(III) — "tris" because "triethylenediamine" would sound like three ethylenediamine molecules (which is correct, but "tris" is clearer).
7. Anionic Complexes: The "-ate" Suffix …
The key idea is that a ligand must have at least one lone pair of electrons available for donation to a metal centre.
- Check each species for a lone pair:
- NO: Has an unpaired electron and a lone pair on nitrogen — can act as a ligand.
- NH4+: All four hydrogens are bonded; nitrogen has no lone pair — cannot donate electrons.
- NH2CH2CH2NH2 (ethylenediamine): Each nitrogen has a lone pair — a classic bidentate ligand. …
A ligand must have at least one lone pair of electrons to donate to a metal centre. NH4+ has no lone pair on nitrogen (all four bonds are used), so it cannot act as a ligand. The correct answer is (ii).
To decide whether a species can be a ligand, you need to recall the fundamental definition: a ligand is an ion or molecule that donates a pair of electrons to a central metal atom to form a coordinate bond. That means the species must possess at least one lone pair of electrons that is available for donation.
Let’s examine each option with this idea in mind.
-
Option (i): NO (Nitric oxide)
Nitric oxide has an unpaired electron and a lone pair on nitrogen. It is a well-known ligand (often called nitrosyl) that can donate its lone pair to a metal. In fact, it forms stable complexes like [Fe(NO)(H2O)5]2+. So it is expected to be a ligand.
-
Option (ii): NH4+ (Ammonium ion)
In NH4+, nitrogen is bonded to four hydrogen atoms via four sigma bonds. All four valence electrons of nitrogen are used in these bonds — there is no lone pair left. Without a lone pair, it cannot donate electrons to a metal.
Watch outA common mistake is to confuse NH4+ with NH3. Ammonia (NH3) has a lone pair and is a classic ligand, but the ammonium ion has lost that lone pair by forming a fourth bond to H+. They are chemically different species.
Therefore, NH4+ cannot act as a ligand.
-
Option (iii): NH2CH2CH2NH2 (Ethylenediamine) …
Concept: Ligands and Donor Atoms
A ligand is a molecule or ion that donates a lone pair of electrons to a central metal atom/ion to form a coordinate bond. For a species to act as a ligand, it must have at least one lone pair of electrons available for donation.
Method: Lone Pair Availability Check
Step 1: Identify the donor atom(s) in each species.
Step 2: Check if the donor atom has a lone pair that is free to donate.
Step 3: If no lone pair exists, the species cannot act as a ligand.
Applying the method:
| Species | Donor atom(s) | Lone pair available? | Ligand? |
|---|---|---|---|
| NO | N | Yes (N has a lone pair) | ✓ Yes |
| NH₄⁺ | N | No — all 4 bonds to H, no lone pair left | ✗ No |
Common Mistakes: Identifying Ligands in Coordination Chemistry
The Concept in Brief
A ligand is a molecule or ion that donates a lone pair of electrons to a central metal atom/ion to form a coordinate bond. For a species to act as a ligand, it must have at least one lone pair available for donation.
Mistake #1: Assuming All Neutral Molecules Are Ligands
The error: Students think that because NO and CO are neutral, they automatically qualify as ligands. They forget to check if the lone pair is actually available for donation.
Why it’s wrong:
- CO has a lone pair on carbon and is a classic ligand (carbonyl).
- NO also has a lone pair on nitrogen and acts as a ligand (nitrosyl). Both are valid ligands — the mistake is ruling them out without checking.
How to avoid:
- Always check for lone pairs on the atom that would donate.
- Neutral molecules can be ligands, but only if they have a free lone pair.
Mistake #2: Confusing NH4+ with NH3
The error: Students see nitrogen and hydrogen and assume NH4+ can donate like NH3.
Why it’s wrong:
- NH3 has a lone pair on nitrogen → acts as a ligand.
- NH4+ has no lone pair — all four bonds are used, and the positive charge means no extra electrons to donate.
How to avoid:
- Count total valence electrons and bond pairs.
- If every valence electron is used in bonding (and there’s a positive charge), there is no lone pair left.
- Key check: NH4+ is not a ligand; NH3 is.
Mistake #3: Overlooking the Role of Charge
The error: Students ignore the charge on a species when deciding if it can donate electrons.
Why it’s wrong:
- A positive charge often means the species has lost electrons — making lone pairs less likely.
- NH4+ is a classic example: it’s electron-deficient, not electron-rich.
How to avoid:
- For cations, ask: Does this ion still have a lone pair?
- For anions (like Cl−, CN−), they usually have extra lone pairs → good ligands.
- For neutral species, check the Lewis structure carefully.
Mistake #4: Thinking “Bigger Molecule = Always a Ligand” …
- Higher Secondary (+2 Stage) Examination 2025Set ANNUAL1 markQ.Write the IUPAC formula of the complex compound pentaamminenitrito-O-cobalt(III) chloride.
›Reveal solutionSolution
'Pentaammine' gives 5 NH3 ligands, 'nitrito-O' gives the nitrite ion bonded through its oxygen (ONO-), and 'cobalt(III)' fixes the metal's oxidation state at +3, needing 2 Cl- as counter ions.
Step 1 - decode the name. 'Pentaammine' = five NH3 (neutral) ligands. 'Nitrito-O' = the nitrite ligand (NO2-) coordinated through its oxygen atom, written as -ONO (as opposed to 'nitrito-N' which would coordinate through nitrogen, written as -NO2). 'Cobalt(III)' = the central metal is Co in the +3 oxidation state.
…
- Higher Secondary (+2 Stage) Examination 2024Set ANNUAL1 markQ.Write the IUPAC name of the compound K3[Fe(C2O4)3].
›Reveal solutionSolution
Naming K3[Fe(C2O4)3]: the cation (potassium) is named first, then the anionic complex, with oxalate (bidentate, named "oxalato") counted using "tris" (rather than "tri") since it is itself a compound ligand name, ending in "-ate" with the metal's oxidation state in Roman numerals because the complex ion is anionic.
Working out Fe's oxidation state: overall charge on 3K+ is +3, so the complex ion [Fe(C2O4)3] must be 3– overall. Oxalate (C2O4^2-) contributes 3 × (–2) = –6.
x + (–6) = –3 → x = +3
So iron is in the +3 oxidation state.
…
- Higher Secondary (+2 Stage) Examination 2023Set ANNUAL1 markQ.Write the IUPAC name of Na3[Co(NO2)6].
›Reveal solutionSolution
Na3[Co(NO2)6] is an anionic complex; naming it requires the ligand name (nitrito), the metal name with an "-ate" ending, and the oxidation state of cobalt (determined from charge balance) in Roman numerals.
Working out the oxidation state of Co: the complex ion is [Co(NO2)6]^3- (charge balances 3 Na+). Each nitrito ligand, NO2-, carries a charge of -1; with 6 of them: 6 x (-1) = -6. Let the oxidation state of Co be x:
x + (-6) = -3 (overall charge of the complex ion)
x = +3
So cobalt is in the +3 oxidation state.
Naming rules for an anionic complex:
- ligands are named in alphabetical order with a multiplying prefix (nitrito x 6 = hexanitrito)
- since the complex is an ANION, the metal name takes the suffix "-ate": cobalt -> cobaltate …
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