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Q.50 mL of an aqueous solution of glucose C6H12O6C_6H_{12}O_6 (Molar mass: 180 g/mol) contains 6.02×10226.02 \times 10^{22} molecules. The concentration of the solution will be (A) 0.1 M (B) 0.2 M (C) 1.0 M (D) 2.0 M

Tripura TbseCBSE Class XII Board 2020MCQ· 1mImportance★★★★★
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Convert molecules to moles with Avogadro's number, then divide by the volume in litres. The concentration is 2.0 M, option (D).

1. Molecules to moles

n=6.02×10226.02×1023=0.1 moln = \frac{6.02 \times 10^{22}}{6.02 \times 10^{23}} = 0.1\ \text{mol}

2. Volume in litres

V=50 mL=0.050 LV = 50\ \text{mL} = 0.050\ \text{L}

3. Molarity …

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