Skip to content
Exercise 5.1 · Q21

Q.Discuss the continuity of the following functions:

(a) f(x)=sin⁡x+cos⁡xf(x) = \sin x + \cos x
(b) f(x)=sin⁡x−cos⁡xf(x) = \sin x - \cos x
(c) f(x)=sin⁡x⋅cos⁡xf(x) = \sin x \cdot \cos x
Tripura TbseTextbookSubjective· 3mImportance★★★★★
7% · 21/281 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

All three functions — sin⁡x+cos⁡x\sin x + \cos x, sin⁡x−cos⁡x\sin x - \cos x, and sin⁡x⋅cos⁡x\sin x \cdot \cos x — are continuous for every real xx, because they are built from the continuous functions sin⁡x\sin x and cos⁡x\cos x using addition, subtraction, and multiplication, which preserve continuity.

The core idea: continuity at a point

A function ff is continuous at x=ax = a if three things hold: f(a)f(a) is defined, lim⁡x→af(x)\lim_{x \to a} f(x) exists, and the two are equal. But for most functions we meet in school, we don't need to check this from first principles every time. Instead, we use a powerful theorem: if ff and gg are continuous at aa, then f+gf + g, f−gf - g, and f⋅gf \cdot g are also continuous at aa. And we already know that sin⁡x\sin x and cos⁡x\cos x are continuous for all real xx — their graphs have no breaks, jumps, or holes anywhere.

So the problem reduces to a simple check: are we combining sin⁡x\sin x and cos⁡x\cos x using only operations that preserve continuity? Yes — addition, subtraction, and multiplication all do. That's the entire logical backbone.

Let's walk through each case.


1. f(x)=sin⁡x+cos⁡xf(x) = \sin x + \cos x

Both sin⁡x\sin x and cos⁡x\cos x are continuous on R\mathbb{R}. The sum of two continuous functions is continuous. Therefore f(x)=sin⁡x+cos⁡xf(x) = \sin x + \cos x is continuous for every real xx.

Tip

You can also rewrite this as 2sin⁡(x+π/4)\sqrt{2} \sin(x + \pi/4), which is a scaled and shifted sine wave — clearly continuous. But the sum rule is enough.


2. f(x)=sin⁡x−cos⁡xf(x) = \sin x - \cos x

Same logic. Subtraction is just addition of the negative: sin⁡x+(−cos⁡x)\sin x + (-\cos x). Since −cos⁡x-\cos x is continuous (a constant times a continuous function), the difference is continuous everywhere.

So f(x)=sin⁡x−cos⁡xf(x) = \sin x - \cos x is continuous on R\mathbb{R}.

--- …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.