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Q.When does ∣x⃗+y⃗∣=∣x⃗∣+∣y⃗∣|\vec{x}+\vec{y}| = |\vec{x}|+|\vec{y}| hold?

Tripura TbseHigher Secondary (+2 Stage) Examination 2023Subjective· 1mImportance★★★★★
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This is the triangle-inequality equality case: equality holds only when the two vectors point in exactly the same direction.

For any two vectors, ∣x⃗+y⃗∣2=∣x⃗∣2+∣y⃗∣2+2x⃗⋅y⃗=∣x⃗∣2+∣y⃗∣2+2∣x⃗∣∣y⃗∣cos⁡θ|\vec x+\vec y|^2=|\vec x|^2+|\vec y|^2+2\vec x\cdot\vec y=|\vec x|^2+|\vec y|^2+2|\vec x||\vec y|\cos\theta, where θ\theta is the angle between x⃗\vec x and y⃗\vec y.

We want this to equal (∣x⃗∣+∣y⃗∣)2=∣x⃗∣2+∣y⃗∣2+2∣x⃗∣∣y⃗∣(|\vec x|+|\vec y|)^2=|\vec x|^2+|\vec y|^2+2|\vec x||\vec y|.

Comparing, we need cos⁡θ=1\cos\theta=1, i.e. θ=0\theta=0.

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