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Worked Examples · Example 3.3

Q.An electric toaster uses nichrome for its heating element. When a negligibly small current passes through it, its resistance at room temperature (27.0 ∘C27.0\ ^\circ\text{C}) is found to be 75.3 Ω75.3\ \Omega. When the toaster is connected to a 230 V230\ \text{V} supply, the current settles, after a few seconds, to a steady value of 2.68 A2.68\ \text{A}. What is the steady temperature of the nichrome element? The temperature coefficient of resistance of nichrome averaged over the temperature range involved, is 1.70×10−4 ∘C−11.70 \times 10^{-4}\ ^\circ\text{C}^{-1}.

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✓ Free question

The hot resistance is R=VI=2302.68≈85.82 ΩR=\dfrac{V}{I}=\dfrac{230}{2.68}\approx 85.82\ \Omega. Using R=R0[1+α(T−T0)]R=R_0\big[1+\alpha(T-T_0)\big] with full precision throughout gives a steady element temperature of about 849 ∘C\mathbf{849\ ^\circ\text{C}}.

A metal's resistance rises with temperature. At room temperature the nichrome element has a known (cold) resistance R0R_0; once it settles into steady glowing operation, it draws a fixed current from the 230 V230\ \text{V} supply, which fixes its (hot) resistance RR. Comparing the two through the linear temperature law gives the operating temperature.

Given: T0=27.0 ∘CT_0=27.0\ ^\circ\text{C}, R0=75.3 ΩR_0=75.3\ \Omega, V=230 VV=230\ \text{V}, I=2.68 AI=2.68\ \text{A}, α=1.70×10−4 ∘C−1\alpha=1.70\times10^{-4}\ ^\circ\text{C}^{-1} (already an average over the temperature range involved, so the linear law can be used directly).

Step 1 — Hot resistance (Ohm's law):

R=VI=2302.68≈85.82 Ω.R=\frac{V}{I}=\frac{230}{2.68}\approx 85.82\ \Omega.

Step 2 — Temperature dependence of resistance:

R=R0[1+α(T−T0)]⇒RR0−1=α(T−T0).R=R_0\big[1+\alpha(T-T_0)\big]\quad\Rightarrow\quad \frac{R}{R_0}-1=\alpha(T-T_0).

Step 3 — Substitute (keeping full precision):

RR0−1=85.82−75.375.3=10.5275.3≈0.1397.\frac{R}{R_0}-1=\frac{85.82-75.3}{75.3}=\frac{10.52}{75.3}\approx 0.1397.

Step 4 — Solve for T:

T−T0=0.13971.70×10−4≈821.8 ∘C,T=27.0+821.8≈848.8 ∘C≈849 ∘C.T-T_0=\frac{0.1397}{1.70\times10^{-4}}\approx 821.8\ ^\circ\text{C},\qquad T=27.0+821.8\approx 848.8\ ^\circ\text{C}\approx 849\ ^\circ\text{C}.

Note

Rounding the hot resistance to 85.8 Ω85.8\ \Omega before subtracting (instead of carrying the full 85.82 Ω85.82\ \Omega) shifts the answer down to about 847 ∘C847\ ^\circ\text{C} — a 2 ∘C2\ ^\circ\text{C} difference purely from intermediate rounding. Carrying full precision through every step, as above, gives the more accurate ≈849 ∘C\approx 849\ ^\circ\text{C}.

✓Final answer

The steady temperature of the nichrome heating element is approximately 849 ∘C\mathbf{849\ ^\circ\text{C}} (about 8.5×102 ∘C8.5\times10^{2}\ ^\circ\text{C}).

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