Skip to content
Question of 50

Q.Two coaxial solenoids, each of length ℓ and cross-sectional area A, are wound one over the other. If the numbers of turns of the two solenoids are N1 and N2, derive the expression for their mutual inductance. OR

(i) What is mutual induction? [1 mark]
(ii) A jet plane is flying westward at a speed of 1800 km/hr. If the strength of the Earth's magnetic field at that place is 5×10^-4 Tesla and the angle of dip is 30°, what is the potential difference induced between the tips of its wings, which are 25 m apart? [2 marks]
Tripura TbseHigher Secondary (+2 Stage) Examination 2023Subjective· 3mImportance★★★★★
0% · 0/50 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

A current in the first (primary) solenoid creates a magnetic field that also passes entirely through the second (secondary) solenoid wound over it; equating the resulting flux linkage to M·I1 gives the mutual inductance formula.

Let solenoid 1 (the primary, with N1 turns) carry a current I1. Since solenoid 2 (the secondary, with N2 turns) is wound directly over solenoid 1 with the same length ℓ and the same cross-sectional area A, essentially all of the magnetic field produced by solenoid 1 also passes through solenoid 2.

The magnetic field inside a long solenoid carrying current I1 with N1 turns over length ℓ is:

B1 = μ0 (N1/ℓ) I1

…

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.