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Problems · Problem 2.16

Q.A golf ball has a mass of 40 g, and a speed of 45 m/s. If the speed can be measured within accuracy of 2%, calculate the uncertainty in the position.

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The Heisenberg Uncertainty Principle relates the uncertainty in position to the uncertainty in momentum. For a golf ball of mass 40 g moving at 45 m/s with a 2% speed uncertainty, the position uncertainty is about 1.46×10−321.46 \times 10^{-32} m — utterly negligible for macroscopic objects.

The key idea here is the Heisenberg Uncertainty Principle, which states that the product of the uncertainties in position (Δx\Delta x) and momentum (Δp\Delta p) is at least on the order of Planck's constant divided by 4π4\pi:

Δx⋅Δp≥h4π\Delta x \cdot \Delta p \ge \frac{h}{4\pi}

This is not a limitation of measurement instruments — it is a fundamental property of quantum mechanics. For everyday objects like a golf ball, the uncertainty in position turns out to be astronomically small, which is why classical physics works so well in daily life.

Let’s work through it step by step.

  1. Find the momentum of the golf ball.

    Mass m=40 g=0.040 kgm = 40 \text{ g} = 0.040 \text{ kg}.

    Speed v=45 m/sv = 45 \text{ m/s}.

    Momentum p=mv=0.040×45=1.8 kg m/sp = m v = 0.040 \times 45 = 1.8 \text{ kg m/s}.

  2. Determine the uncertainty in speed.

    The speed can be measured within 2% accuracy. That means the uncertainty in speed is:

Δv=2% of 45=0.02×45=0.9 m/s\Delta v = 2\% \text{ of } 45 = 0.02 \times 45 = 0.9 \text{ m/s}

  1. Calculate the uncertainty in momentum. Since mass is known precisely (no uncertainty given), the uncertainty in momentum comes entirely from the uncertainty in speed:

Δp=mΔv=0.040×0.9=0.036 kg m/s\Delta p = m \Delta v = 0.040 \times 0.9 = 0.036 \text{ kg m/s}

  1. Apply the Heisenberg Uncertainty Principle. The minimum possible uncertainty in position is:

Δx≥h4πΔp\Delta x \ge \frac{h}{4\pi \Delta p}

where h=6.626×10−34 J sh = 6.626 \times 10^{-34} \text{ J s} (Planck's constant).

Plug in the numbers:

Δx≥6.626×10−344×3.1416×0.036\Delta x \ge \frac{6.626 \times 10^{-34}}{4 \times 3.1416 \times 0.036}

First compute the denominator:

4πΔp=4×3.1416×0.036≈0.45244\pi \Delta p = 4 \times 3.1416 \times 0.036 \approx 0.4524 …

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