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Worked Examples · Example 5

Q.Find the multiplicative inverse of 2−3i2 - 3i.

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✓ Free question

The multiplicative inverse of a complex number is found by rationalising the denominator using its conjugate. For 2−3i2 - 3i, the inverse is 213+313i\frac{2}{13} + \frac{3}{13}i.

The idea of a multiplicative inverse is simple: for any non-zero number zz, its inverse z−1z^{-1} is the number that satisfies z⋅z−1=1z \cdot z^{-1} = 1. For real numbers, the inverse of aa is just 1a\frac{1}{a}. But for a complex number like 2−3i2 - 3i, writing 12−3i\frac{1}{2 - 3i} isn't helpful — it's not in the standard a+bia + bi form.

The trick is to turn the denominator into a real number. We do this by multiplying numerator and denominator by the complex conjugate of the denominator. The conjugate of a+bia + bi is a−bia - bi; for 2−3i2 - 3i, the conjugate is 2+3i2 + 3i. When you multiply a complex number by its conjugate, you get a purely real result: (a+bi)(a−bi)=a2+b2(a+bi)(a-bi) = a^2 + b^2.

Let's work through it.

  1. Write the inverse as a fraction.

    The multiplicative inverse of 2−3i2 - 3i is 12−3i\frac{1}{2 - 3i}.

  2. Multiply numerator and denominator by the conjugate.

    We use 2+3i2 + 3i, the conjugate of 2−3i2 - 3i:

12−3i×2+3i2+3i=2+3i(2−3i)(2+3i)\frac{1}{2 - 3i} \times \frac{2 + 3i}{2 + 3i} = \frac{2 + 3i}{(2 - 3i)(2 + 3i)}

  1. Simplify the denominator. This is a difference of squares:

(2−3i)(2+3i)=22−(3i)2=4−9i2(2 - 3i)(2 + 3i) = 2^2 - (3i)^2 = 4 - 9i^2

Since i2=−1i^2 = -1, we get:

4−9(−1)=4+9=134 - 9(-1) = 4 + 9 = 13

The denominator is now the real number 13.

  1. Write the result in a+bia + bi form. The numerator is 2+3i2 + 3i, so:

2+3i13=213+313i\frac{2 + 3i}{13} = \frac{2}{13} + \frac{3}{13}i

Tip

You can quickly check your answer: multiply 2−3i2 - 3i by 213+313i\frac{2}{13} + \frac{3}{13}i. The product should simplify to 11 — a good habit for exam verification.

Watch out

A common mistake is forgetting that i2=−1i^2 = -1, not −i-i. In step 3, (3i)2=9i2=−9(3i)^2 = 9i^2 = -9, so 4−(−9)=134 - (-9) = 13. If you treat i2i^2 as −i-i, you'll get the wrong denominator.

✓Final answer

The multiplicative inverse is 213+313i\boxed{\frac{2}{13} + \frac{3}{13}i}.

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