Q.Show that the points , , and are the vertices of a parallelogram , but it is not a rectangle.
The four points form a parallelogram because the midpoints of the diagonals coincide, and it is not a rectangle because the adjacent sides are not perpendicular — their dot product is non-zero.
We need to check two things: first, that these four points are the vertices of a parallelogram (in the order ), and second, that this parallelogram is not a rectangle.
1. The key idea — what makes a parallelogram?
A quadrilateral is a parallelogram if and only if its diagonals bisect each other. That is, the midpoint of diagonal must equal the midpoint of diagonal . This is often simpler than checking that opposite sides are parallel and equal — one calculation instead of four.
The midpoint condition works for any order of vertices, but here the order is given as . So we check diagonals and .
2. Find the midpoints
Midpoint of :
Midpoint of :
They are identical. So the diagonals bisect each other, and is a parallelogram.
3. Now check if it is a rectangle
A rectangle is a parallelogram with all angles . For that, we need adjacent sides to be perpendicular. Let’s take sides and .
Vectors:
Perpendicularity check: two vectors are perpendicular if their dot product is zero.
Since , the sides are not perpendicular. So the angle at is not , and the parallelogram is not a rectangle.
A common mistake is to check only one pair of adjacent sides — that is enough. If any angle is not , the figure cannot be a rectangle. You do not need to check all four angles.
4. Could it be a square or rhombus?
No need — the question only asks to show it is a parallelogram but not a rectangle. We have done both.
The points form a parallelogram (diagonals bisect each other), but it is not a rectangle because .
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