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NCERT Exemplar · Q32

Q.Differentiate with respect to xx: (sec⁡x−1)(sec⁡x+1)(\sec x - 1)(\sec x + 1).

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The expression (sec⁡x−1)(sec⁡x+1)(\sec x - 1)(\sec x + 1) simplifies to sec⁡2x−1=tan⁡2x\sec^2 x - 1 = \tan^2 x using the identity (a−b)(a+b)=a2−b2(a-b)(a+b)=a^2-b^2. Differentiating tan⁡2x\tan^2 x using the chain rule gives the derivative 2tan⁡xsec⁡2x2\tan x \sec^2 x.

Concept First: Why Simplify Before Differentiating

When you see a product of two binomials like (sec⁡x−1)(sec⁡x+1)(\sec x - 1)(\sec x + 1), your first instinct might be to reach for the product rule. But here's the thing — the product rule works, but it's unnecessarily messy. The expression is a classic difference of squares: (a−b)(a+b)=a2−b2(a-b)(a+b) = a^2 - b^2.

Recognising this pattern saves time and reduces the chance of algebraic errors. Once simplified, the differentiation becomes a straightforward application of the chain rule — a technique you'll use constantly in calculus.

Tip

Always check if a product can be simplified using algebraic identities before applying the product rule. The difference of squares (a−b)(a+b)=a2−b2(a-b)(a+b) = a^2 - b^2 is one of the most common shortcuts.

Step-by-Step Solution

1. Simplify the expression using the difference of squares

Let a=sec⁡xa = \sec x and b=1b = 1. Then:

(sec⁡x−1)(sec⁡x+1)=sec⁡2x−12=sec⁡2x−1(\sec x - 1)(\sec x + 1) = \sec^2 x - 1^2 = \sec^2 x - 1

2. Apply the Pythagorean identity for secant and tangent

Recall the fundamental identity:

sec⁡2x=1+tan⁡2x\sec^2 x = 1 + \tan^2 x

Therefore:

sec⁡2x−1=tan⁡2x\sec^2 x - 1 = \tan^2 x

So the original expression simplifies neatly to tan⁡2x\tan^2 x.

sec⁡2x−1=tan⁡2x\sec^2 x - 1 = \tan^2 x

3. Differentiate tan⁡2x\tan^2 x using the chain rule

We want ddx(tan⁡2x)\frac{d}{dx}(\tan^2 x). Think of this as [f(x)]2[f(x)]^2 where f(x)=tan⁡xf(x) = \tan x.

The chain rule says: derivative of the outer function (square) times derivative of the inner function (tan).

  • Outer: u2u^2 has derivative 2u2u
  • Inner: tan⁡x\tan x has derivative sec⁡2x\sec^2 x

So: …

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