Skip to content
Miscellaneous Exercise · Q26

Q.Find the derivative of 4x+5sin⁡x3x+7cos⁡x\dfrac{4x + 5\sin x}{3x + 7\cos x}.

Uttar Pradesh UpmspTextbookSubjective· 3mImportance★★★★★est
52% · 91/175 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Use the Quotient Rule: if y=uvy = \frac{u}{v}, then y′=u′v−uv′v2y' = \frac{u'v - uv'}{v^2}. Here u=4x+5sin⁡xu = 4x + 5\sin x, v=3x+7cos⁡xv = 3x + 7\cos x. The derivative is (4+5cos⁡x)(3x+7cos⁡x)−(4x+5sin⁡x)(3−7sin⁡x)(3x+7cos⁡x)2\frac{(4 + 5\cos x)(3x + 7\cos x) - (4x + 5\sin x)(3 - 7\sin x)}{(3x + 7\cos x)^2}.

The Quotient Rule is the natural choice whenever you have one function divided by another. It’s really just the Product Rule in disguise — think of uv\frac{u}{v} as u⋅v−1u \cdot v^{-1} — but the standard form is cleaner to apply directly.

The key insight: you differentiate the numerator times the denominator, minus the numerator times the derivative of the denominator, all over the denominator squared. The order matters — numerator first, then denominator — and the minus sign is where most mistakes happen.

Let’s work through it step by step.

1. Identify uu and vv

We have:

u=4x+5sin⁡xu = 4x + 5\sin x

v=3x+7cos⁡xv = 3x + 7\cos x

2. Differentiate each separately

u′=4+5cos⁡xu' = 4 + 5\cos x (derivative of 4x4x is 44, derivative of 5sin⁡x5\sin x is 5cos⁡x5\cos x)

v′=3−7sin⁡xv' = 3 - 7\sin x (derivative of 3x3x is 33, derivative of 7cos⁡x7\cos x is −7sin⁡x-7\sin x)

Watch out

A common slip: forgetting that the derivative of cos⁡x\cos x is −sin⁡x-\sin x, so 7cos⁡x7\cos x differentiates to −7sin⁡x-7\sin x, not +7sin⁡x+7\sin x. That minus sign changes everything.

3. Apply the Quotient Rule

y′=u′v−uv′v2y' = \frac{u'v - uv'}{v^2}

Substitute:

y′=(4+5cos⁡x)(3x+7cos⁡x)−(4x+5sin⁡x)(3−7sin⁡x)(3x+7cos⁡x)2y' = \frac{(4 + 5\cos x)(3x + 7\cos x) - (4x + 5\sin x)(3 - 7\sin x)}{(3x + 7\cos x)^2}

4. That’s the derivative — no need to expand further unless asked …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.