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Miscellaneous Examples · Example 9

Q.Solve −8≤5x−3<7-8 \le 5x - 3 < 7.

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✓ Free question

Isolate xx by adding 33 to all parts, then dividing by 55; the solution is −1≤x<2-1 \le x < 2.

A compound inequality like this one chains two conditions together: 5x−35x - 3 must be at least −8-8 and strictly less than 77 at the same time. The key insight is that we can perform the same operation on all three parts simultaneously, provided we respect the rules that govern inequalities. Since we'll only add and divide by a positive number here, the inequality signs stay put.

Think of this as finding the overlap of two half-lines on the number line. We're hunting for all xx that satisfy both constraints.

Solution

1. Add 33 to all three parts

We want to peel away the "−3-3" attached to 5x5x. Adding 33 everywhere preserves the inequality relationships:

−8+3≤5x−3+3<7+3-8 + 3 \le 5x - 3 + 3 < 7 + 3

−5≤5x<10-5 \le 5x < 10

2. Divide all parts by 55

Now isolate xx by dividing through by 55. Since 5>05 > 0, the inequality directions remain unchanged:

−55≤5x5<105\frac{-5}{5} \le \frac{5x}{5} < \frac{10}{5}

−1≤x<2-1 \le x < 2

This tells us xx lives in the interval [−1,2)[-1, 2): it includes −1-1 (closed bracket) but excludes 22 (open bracket).

Tip

When dividing or multiplying an inequality by a negative number, you must flip the inequality signs. Here we divided by positive 55, so no flip was needed.

3. Interpret the result

The solution set is all real numbers from −1-1 up to, but not including, 22. On a number line, you'd draw a solid dot at −1-1 and an open circle at 22, shading everything in between.

✓Final answer

The solution is −1≤x<2\boxed{-1 \le x < 2} or, in interval notation, [−1,2)[-1, 2).

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