Exercise 13.2 · Q7
Q.
Find the mean and variance for the following frequency distribution.
| Classes | Frequencies |
|---|---|
| 0-30 | 2 |
| 30-60 | 3 |
| 60-90 | 5 |
| 90-120 | 10 |
| 120-150 | 3 |
| 150-180 | 5 |
| 180-210 | 2 |
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Start your 14-day free trial to unlock the full solution →Using class midpoints, the mean is 107 and the variance is 2276.
Because the data is grouped, each class is represented by its midpoint . We find the mean as a frequency-weighted average, then the variance as the frequency-weighted average of squared deviations from that mean.
Step 1 — Midpoints, total frequency, and .
Midpoints: 15, 45, 75, 105, 135, 165, 195.
| Class | |||
|---|---|---|---|
| 0–30 | 2 | 15 | 30 |
| 30–60 | 3 | 45 | 135 |
| 60–90 | 5 | 75 | 375 |
| 90–120 | 10 | 105 | 1050 |
| 120–150 | 3 | 135 | 405 |
| 150–180 | 5 | 165 | 825 |
| 180–210 | 2 | 195 | 390 |
| Total | 30 | 3210 |
Step 2 — Mean.
Step 3 — Squared deviations from the mean, weighted by frequency.
| | | | | |
|---|---|---|---|---| …
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