NCERT Exemplar · Q3
Q.Two temperature scales A and B are related by a straight-line graph on which temperature on scale A (in °A) is plotted on the vertical axis and temperature on scale B (in °B) on the horizontal axis. Between the lower fixed point and the upper fixed point there are 150 equal divisions on scale A and 100 equal divisions on scale B. The straight line passes through the lower fixed point at A (which reads B) and the upper fixed point at A (which reads B). The relationship for conversion between the two scales is given by
(a)
(b)
(c)
(d)
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✓ Free question
A reading on one linear temperature scale converts to another by matching the fraction of the way each reading lies between the two scales' common fixed points. Here the lower fixed point is A B and the upper fixed point is A B, with 150 divisions on A and 100 on B between them. This gives — option (B).
Concept
Both scales are linear (equally spaced divisions), so plotting against is a straight line. Any two linear scales are related by matching the fraction of the interval between their common fixed points.
Reading the graph
- Lower fixed point (bottom of the line): A, B.
- Upper fixed point (top of the line): A, B.
- Interval on A: divisions; interval on B: divisions.
Why this formula
For a linear scale a reading is fixed by the fraction . The same physical temperature must give the same fraction on both scales:
Steps
- Scale A: fraction .
- Scale B: fraction .
- Equate the two fractions: .
Why the distractors are wrong
- (A) uses (subtracts the upper fixed point) and swaps the divisions — both errors.
- (C) subtracts 180 from , but the fixed point belongs to scale A, not B; the axes/divisions are interchanged.
- (D) contains and a division of , neither of which appears on either scale.
✓Final answer
Option (B): .
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